Login or Register to Ask a Question and Join Our Community


Shell Programming and Scripting

sed to do replace on line above

Login to Discuss or Reply to this Discussion in Our Community

 
Thread Tools Search this Thread
Top Forums Shell Programming and Scripting sed to do replace on line above
# 8  
Old 12-11-2011
i tried scrutinizer one liner.. but i am getting error..
sorry but i am new to awk.. is it the complete command or just the syntax
# 9  
Old 12-11-2011
Are you on Solaris? If so use /usr/xpg4/bin/awk or nawk instead of awk
This User Gave Thanks to Scrutinizer For This Post:
chidori
# 10  
Old 12-11-2011
wow it worked.. but whats the difference between
Code:
/usr/bin/awk

and
Code:
/usr/xpg4/bin/awk

# 11  
Old 12-11-2011
Hi, /usr/xpg4/bin/awk is the POSIX (standard) version of awk on Solaris. The default awk version on Solaris (/usr/bin/awk) is outdated and is best avoided.
This User Gave Thanks to Scrutinizer For This Post:
chidori
# 12  
Old 12-12-2011
Just for the record: a sed solution would be:
Code:
sed  '/pattern/!{x;1d};/pattern/{x;s/old/new/;n;x};${p;x}' infile

Where 'pattern' is what you want to match on; and s/old/new/ is what you want to substitute with in the previous line.
Commands explained:
Code:
sed '
  /pattern/!{x;1d};               #line doesn't contain "pattern". Exchange the pattern buffer with hold buffer (x) 
                                  #and if it's the first line, delete (otherwise an empty line is printed at the beginning)
  /pattern/{x; s/old/new/; n;x};  #pattern found; exchange pat and hold  buffs (x), 
                                  #do substitution (s), 
                                  #print current pattern space (changed line) and  take a new line (n),
                                  #and exchange the new line with the line stashed in  hold buffer (x)
  ${p;x}                          #print the pattern space and the hold space on the last line
' infile
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Replace values in script reading line by line using sed

Hi all, Let's say I have a script calling for the two variables PA_VALUE and PB_VALUE. for pa in PA_VALUE blah blah do for pb in PB_VALUE blah blah do I have a text file with two columns of values for PA and PB. 14.5 16.7 7.8 9.5 5.6 3.6 etc etc I would like to read this... (7 Replies)
Discussion started by: crimsonengineer
7 Replies

2. Shell Programming and Scripting

sed command to replace a line in a file using line number from the output of a pipe.

Sed command to replace a line in a file using line number from the output of a pipe. Is it possible to replace a whole line piped from someother command into a file at paritcular line... here is some basic execution flow.. the line number is 412 lineNo=412 Now i have a line... (1 Reply)
Discussion started by: vivek d r
1 Replies

3. Shell Programming and Scripting

Multiple line search, replace second line, using awk or sed

All, I appreciate any help you can offer here as this is well beyond my grasp of awk/sed... I have an input file similar to: &LOG &LOG Part: "@DB/TC10000021855/--F" &LOG &LOG &LOG Part: "@DB/TC10000021852/--F" &LOG Cloning_Action: RETAIN &LOG Part: "@DB/TCCP000010713/--A" &LOG &LOG... (5 Replies)
Discussion started by: KarmaPoliceT2
5 Replies

4. Shell Programming and Scripting

sed command to replace a line at a specific line number with some other line

my requirement is, consider a file output cat output blah sdjfhjkd jsdfhjksdh sdfs 23423 sdfsdf sdf"sdfsdf"sdfsdf"""""dsf hellow there this doesnt look good et cetc etc etcetera i want to replace a line of line number 4 ("this doesnt look good") with some other line ... (3 Replies)
Discussion started by: vivek d r
3 Replies

5. Shell Programming and Scripting

Replace line with sed on OS X

So, I want to, in a script, do an in-line replacement of a line in a file. Piece of cake in Linux with GNU sed. With OSX and BSD sed, not so much. I've been Googling, but nothing is really helping... either an answer is for a use case different enough from what I want to do, or it's something... (10 Replies)
Discussion started by: jnojr
10 Replies

6. Shell Programming and Scripting

I need to know how to replace a line after a pattern match with an empty line using SED

Hi How Are you? I am doing fine! I need to go now? I will see you tomorrow! Basically I need to replace the entire line containing "doing" with a blank line: I need to the following output: Hi How Are you? I need to go now? I will see you tomorrow! Thanks in advance.... (1 Reply)
Discussion started by: sags007_99
1 Replies

7. Shell Programming and Scripting

sed to replace a line with modified line in same file

i have few lines in a file... i am reading them in a while loop so a particular line is held is $line1.. consider a modified line is held in $line2.... i want to replace $line1 with $line2 in the same file... how to do it..? i have come up till the below code sed "s/$line1/$line2/g" tmpfile.sql... (5 Replies)
Discussion started by: vivek d r
5 Replies

8. Shell Programming and Scripting

sed to replace <cr><cr><cr> in a line with <cr>

Hi, Please help me with the sed command for the following scenario: I've in abc.txt, asdasdada<cr>aasdsad<cr><cr>asdasdfsdfs<cr><cr><cr>asdsada<cr>adasd<cr>daasdaasd<cr><cr><cr> I want a sed command to do asdasdada<cr>aasdsad<cr>asdasdfsdfs<cr>asdsada<cr>adasd<cr>daasdaasd<cr> ... (13 Replies)
Discussion started by: skpvalvekar
13 Replies

9. Shell Programming and Scripting

How to replace one line with three in sed

Hi, I have a problem. I want to use SED to replace one line with three It looks like: PARAM='first_line,second_line,third_line' And in file: blablabla blablabla PARAM blablabla blablabla blablabla All I want is to change this into: blablabla blablabla first_line second_line... (6 Replies)
Discussion started by: ch0sen
6 Replies

10. Shell Programming and Scripting

sed - Replace Line which contains the Pattern match with a new line

I need to replace the line containing "STAGE_DB" with the line "STAGE_DB $DB # database that contains the table being loaded ($workingDB)" Here $DB is passed during the runtime. How can I do this? Thanks, Kousikan (2 Replies)
Discussion started by: kousikan
2 Replies
Login or Register to Ask a Question