check if a string is numeric


 
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# 15  
Old 11-14-2011
Hi Shamrock

Thank you so much .That worked.
And in the code I modified it to this.
Code:
if  [[ "$var" != ?(""|*([+-])*([0-9])*(.)*([0-9])) ]]; then
 
 
If var != null or var!=numeric ,

only then my shell will contiue. otherwise it will exit the process.

Can you tell me about the " ? "that you used in the code?
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CheckDigits::M43_001(3pm)				User Contributed Perl Documentation				 CheckDigits::M43_001(3pm)

NAME
CheckDigits::M43_001 - compute check digits for Code-39 SYNOPSIS
use Algorithm::CheckDigits; $c39 = CheckDigits('code_39'); if ($c39->is_valid('AB-123K')) { # do something } $cn = $c39->complete('AB-123'); # $cn = 'AB-123K' $cd = $c39->checkdigit('AB-123K'); # $cd = 'K' $bn = $c39->basenumber('AB-123K'); # $bn = 'AB-123' DESCRIPTION
ALGORITHM 1. After replacing all non numeric letters with their respective values, the sum of all numbers is computers 2. The checkdigit is the sum from step 1 taken modulo 43. METHODS is_valid($number) Returns true only if $number consists solely of numbers and the last digit is a valid check digit according to the algorithm given above. Returns false otherwise, complete($number) The check digit for $number is computed and concatenated to the end of $number. Returns the complete number with check digit or '' if $number does not consist solely of digits and spaces. basenumber($number) Returns the basenumber of $number if $number has a valid check digit. Return '' otherwise. checkdigit($number) Returns the checkdigit of $number if $number has a valid check digit. Return '' otherwise. EXPORT None by default. AUTHOR
Mathias Weidner, <mathias@weidner.in-bad-schmiedeberg.de> SEE ALSO
perl, CheckDigits, www.pruefziffernberechnung.de. perl v5.10.0 2008-05-17 CheckDigits::M43_001(3pm)