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Shell Programming and Scripting

cut the some part in filename

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# 1  
Old 11-03-2011
cut the some part in filename
Hi All,

I have the file & name is "/a/b/c/d/e/xyz.dat"

I need "/a/b/c/d/e/" from the above file name.

I tryning with echo and awk. But it not come. Please help me in this regard.


Thanks & Regards,
Dathu
# 2  
Old 11-03-2011
Maybe:
Code:
# pathAndFile="/a/b/c/d/e/xyz.dat"
# dirname "${pathAndFile}"
/a/b/c/d/e
# basename "${pathAndFile}"
xyz.dat

# 3  
Old 11-03-2011
Using awk, here is half your request
Code:
$ echo /a/b/c/d/e/xyz.dat | awk -F'/' '{print $NF}'
xyz.dat

# 4  
Old 11-03-2011
Without external external commands:

Code:
var="/a/b/c/d/e/xyz.dat"

path=${var%/*}

file=${var##*/}

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