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TRIM a string in shell script

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# 1  
Old 10-05-2011
TRIM a string in shell script
HI,
I have a string "NZ-deploy-mode-1.15-Linux.x86_64.rpm"

I want to get the string before -1 ie "NZ-deploy-mode"

Input is "NZ-deploy-mode-1.15-Linux.x86_64.rpm"

expected output is "NZ-deploy-mode"




How can I do that in shell script?

Thanks in advance.
# 2  
Old 10-05-2011
Code:
$ xxx=NZ-deploy-mode-1.15-Linux.x86_64.rpm
$ echo ${xxx%%-1*}
NZ-deploy-mode
$

Jean-Pierre.
# 3  
Old 10-05-2011
below one of ways to do it:
Code:
>
> a="NZ-deploy-mode-1.15-Linux.x86_64.rpm"
> echo $a | cut -f 1,2,3 -d -
NZ-deploy-mode
>

# 4  
Old 10-05-2011
Code:
$ inp="NZ-deploy-mode-1.15-Linux.x86_64.rpm"
$ echo $inp | awk -F- '{print $1"-"$2"-"$3}'
NZ-deploy-mode
$ echo $inp | cut -d'-' -f1-3
NZ-deploy-mode
$

# 5  
Old 10-05-2011
You can use sed as:
Code:
sed 's/-1.15-Linux.x86_64.rpm//'

Eg:
Code:
inp=NZ-deploy-mode-1.15-Linux.x86_64.rpm
abc@abc.com$ echo $inp | sed 's/-1.15-Linux.x86_64.rpm//'
NZ-deploy-mode


Thanks!!!
# 6  
Old 10-05-2011
Try this one.
Code:
$ echo "NZ-deploy-mode-1.15-Linux.x86_64.rpm" | sed 's/-1.*//'
NZ-deploy-mode

# 7  
Old 10-05-2011
@All thank you so much Smilie
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