TRIM a string in shell script

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# 1  
Old 10-05-2011
TRIM a string in shell script

I have a string "NZ-deploy-mode-1.15-Linux.x86_64.rpm"

I want to get the string before -1 ie "NZ-deploy-mode"

Input is "NZ-deploy-mode-1.15-Linux.x86_64.rpm"

expected output is "NZ-deploy-mode"

How can I do that in shell script?

Thanks in advance.
# 2  
Old 10-05-2011
$ xxx=NZ-deploy-mode-1.15-Linux.x86_64.rpm
$ echo ${xxx%%-1*}

# 3  
Old 10-05-2011
below one of ways to do it:
> a="NZ-deploy-mode-1.15-Linux.x86_64.rpm"
> echo $a | cut -f 1,2,3 -d -

# 4  
Old 10-05-2011
$ inp="NZ-deploy-mode-1.15-Linux.x86_64.rpm"
$ echo $inp | awk -F- '{print $1"-"$2"-"$3}'
$ echo $inp | cut -d'-' -f1-3

# 5  
Old 10-05-2011
You can use sed as:
sed 's/-1.15-Linux.x86_64.rpm//'

inp=NZ-deploy-mode-1.15-Linux.x86_64.rpm$ echo $inp | sed 's/-1.15-Linux.x86_64.rpm//'

# 6  
Old 10-05-2011
Try this one.

$ echo "NZ-deploy-mode-1.15-Linux.x86_64.rpm" | sed 's/-1.*//'

# 7  
Old 10-05-2011
@All thank you so much Smilie
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