automatically check job status

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# 1  
Old 10-03-2011
Question automatically check job status

I have written a BASH script to autmatically start several jobs. I want to add additional function to the script so it would check these jobs from time to time (the jobs could take as short as 2 hours or as long as 1 day to finish). If a job is done, check the log file and output the error into a new file.

Could anyone give me some help here? I am a noobs to scripting. Thanks a lot!
# 2  
Old 10-03-2011
You can make sure of crontab and a script like this

#script name : monitor

#the actual job names to be monitored
jobs="job1 job2"
for j in $jobs
  pgrep $j >/dev/null
  if [ $? -ne 0 ]
    grep -i "Error" $log_path/$j >> /tmp/error.log

And crontab entry. The monitor script will run every 10 minutes. For more info man crontab
*/10 * * * * /tmp/test/monitor

Assuming all the log will be at a common path say /tmp/<job name>.log

# 3  
Old 10-03-2011
Thanks ahamed! How can i use the script to save the job names for those jobs i already submit? I guess I should do sth when I submit each of them in my loop, but don't know what command should do it.

---------- Post updated at 04:32 PM ---------- Previous update was at 01:53 PM ----------

My thought was to keep a list of pid, update this list once a while, e.g. every 5 minutes. once the list is empty, generate the error file from the logs.

suppose one of the pid in the list is 11335:

testa=`ps -u myid | grep " 11335 "`
if [$testa !="" ]
echo "find ksh"
echo "not find ksh"

Apparently the comparison is not correct ([$testa !="" ]). I don't know in this situation, how could I compare the return with empty (string)?

Last edited by momentum; 10-04-2011 at 10:26 AM..
# 4  
Old 10-03-2011
Yes, you can make use of pid also.

if [ ! -z "$testa" ]
   echo "find ksh"
   echo "not find ksh"

PS : Use code tags!

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