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Sorting within a record using AWK

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# 8  
Old 09-22-2011
Another Perl solution:

Code:
perl -lane'
  if (/^Module/) {
    $k and print join $/, $k, map $_->[1], sort {
      $a->[0] <=> $b->[0]
      } @a;
    $k = $_; @a = (); next
    }
  push @a, [$F[3] =~ /NA/ ? 99999 : $F[3], $_];
  END {
    print join $/, $k, map $_->[1], sort {
      $a->[0] <=> $b->[0]
      } @a
    }' infile

# 9  
Old 09-23-2011
MySQL
Quote:
Originally Posted by binlib
Code:
awk '{
  if (/^Module :/) {
    close("sort -k4,4n")
    print
  } else print |"sort -k4,4n";
}
END { close("sort -k4,4n") } # not necessary
' infile

This will put the "NA"s together with the 0s, not the last.
Thank you very much. You have given a very elegant solution. Smilie
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