extract information from a log file (last days)


 
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# 1  
Old 09-19-2011
extract information from a log file (last days)

I'm still new to bash script , I have a log file and I want to extract the items within the last 5 days . and also within the last 10 hours

the log file is like this : it has 14000 items started from march 2002 to january 2003

[31/Mar/2002:19:30:41
.
.
.
[01/Jan/2003:12:55:15
[01/Jan/2003:12:55:16
[01/Jan/2003:12:55:16
[01/Jan/2003:12:55:16
[01/Jan/2003:12:55:17
[01/Jan/2003:12:55:17
[01/Jan/2003:12:55:18
[01/Jan/2003:12:55:18
[01/Jan/2003:12:55:18
[01/Jan/2003:12:55:19
[01/Jan/2003:12:55:19
[01/Jan/2003:12:55:20
[01/Jan/2003:12:55:20
[01/Jan/2003:12:55:20
[01/Jan/2003:12:55:21

is it possible to write it like this :
Code:
awk '{print $4}' < *.log |uniq -c|sort -g|tail -10

but still its not what I want

Last edited by vbe; 09-19-2011 at 02:46 PM.. Reason: please use code tags where needed
matarsak
# 2  
Old 09-19-2011
I am not sure what are you trying to get at here...as Jan 2003 isnt even the last 5 years and you want the last 5 days Smilie
# 3  
Old 09-19-2011
I'm just practicing and I work on this log file as an example ! how the bash could shows the last x days of this log file ? the last X days that is available there not now !
matarsak
# 4  
Old 09-19-2011
Date math isn't trivial, many systems don't have easy ways to manipulate and compare dates from the shell. If you manipulate dates into YYYYMMDDHHMMSS order they can be compared alphabetically, but you can't do date arithmetic from that.

If you have GNU awk(usually found in Linux) this may be a starting point:

Code:
gawk -v EDATE="26/Oct/2002:21:02:19" 'BEGIN {
        # Set up arrays for name-to-monthnumber
        split("Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec", MON, "|");
        for(N=1; N<=12; N++) MNUM[MON[N]]=sprintf("%02d", N);

        # Split [DD/MON/YYYY:HH:MM:SS into DD MM YYYY HH MM SS stored in D[1]-D[6].
        split(EDATE, D, "[:/]");
        # Convert "YYYY MM DD HH MM SS" into epoch time, i.e. seconds since 1970
        EDATE=mktime(D[3] " " MNUM[D[2]] " " D[1] " " D[4] " " D[5] " " D[6]);
        # Starting date is 5 days earlier
        SDATE=EDATE-(60*60*24*5);
}

{
                # Need the \\[ in there to ignore the [ at the beginning of the line
                split($1, D, "[\\[:/]");
                DATE=mktime(D[4] " " MNUM[D[3]] " " D[2] " " D[5] " " D[6] " " D[7]);
                # Print the line if it falls in the correct range
                if((DATE >= SDATE) && (DATE <= EDATE)) print;
        }' < datafile

Try getting EDATE from the last lilne of the file, with tail -1

Last edited by Corona688; 09-19-2011 at 02:13 PM..
# 5  
Old 09-19-2011
Can you post a sample of the logfile showing the exact format of the date and time stamp entries.
# 6  
Old 09-19-2011
here the example of log file :
Code:
172.16.0.3 - - [31/Mar/2002:19:30:41 +0200]
127.0.0.1 - stefan [01/Apr/2002:12:17:23 +0200]
213.64.153.92 - - [26/Sep/2002:02:01:58 +0200]
213.97.240.226 - - [28/Sep/2002:03:50:58 +0200] 
213.64.214.124 - - [29/Sep/2002:09:56:04 +0200]
.......
213.46.27.204 - - [01/Jan/2003:12:55:21 +0100]


Last edited by Franklin52; 09-19-2011 at 02:47 PM.. Reason: Please use code tags for data and code samples, thank you
matarsak
# 7  
Old 09-19-2011
In that case:

Code:
gawk -v EDATE="26/Oct/2002:21:02:19" 'BEGIN {
        # Set up arrays for name-to-monthnumber
        split("Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec", MON, "|");
        for(N=1; N<=12; N++) MNUM[MON[N]]=sprintf("%02d", N);

        # Split [DD/MON/YYYY:HH:MM:SS into DD MM YYYY HH MM SS stored in D[1]-D[6].
        split(EDATE, D, "[:/]");
        # Convert "YYYY MM DD HH MM SS" into epoch time, i.e. seconds since 1970
        EDATE=mktime(D[3] " " MNUM[D[2]] " " D[1] " " D[4] " " D[5] " " D[6]);
        # Starting date is 5 days earlier
        SDATE=EDATE-(60*60*24*5);
}

{
                # Need the \\[ in there to ignore the [ at the beginning of the field
                split($(NF-1), D, "[\\[:/]");
                DATE=mktime(D[4] " " MNUM[D[3]] " " D[2] " " D[5] " " D[6] " " D[7]);
                # Print the line if it falls in the correct range
                if((DATE >= SDATE) && (DATE <= EDATE)) print;
        }' < datafile

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