Getting PID from filename


 
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# 1  
Old 09-12-2011
Getting PID from filename

Hi,

Any idea the shortest way to get the PID of the filename?

Code:
T201108221033_P001736.Sep_5_1457.csv

The sample pid is 1736, but it could be 5 or 6 digits depends on process count.
# 2  
Old 09-12-2011
if all your filenames are in this pattern as your example, take a look the test and output below:
Code:
 echo "T201108221033_P001736.Sep_5_1457.csv" |awk -F'[P.]' '{print $2}'
001736

if you don't want the leading zeros:
Code:
kent$  echo "T201108221033_P001736.Sep_5_1457.csv" |awk -F'[P.]' '{print $2*1}'
1736

This User Gave Thanks to sk1418 For This Post:
# 3  
Old 09-12-2011
Thanks working, anyway i have to replace "awk" with "nawk". not sure why it was not working on Solaris 10
# 4  
Old 09-12-2011
On Solaris, awk is a very old version and you generally should use nawk if you can.
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