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search pattern that has spaces with nawk

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# 1  
Old 08-12-2011
search pattern that has spaces with nawk
Hi guys,

I need a help ! I need do grab some string from file and then count n lines after that pattern. This is working fine, but my problem is that the string to be searched has spaces within, like an example :

LINK [2] COUNTERS

what I am using is:
Code:
nawk 'c-->0;$0~\s\{if(b)for(c=b+1;c>1;c--)print r[(NR-c+1)%b];\
print;c=a}b{r[NR%b]=$0}' b=0 a=1 s="LINK [2] COUNTERS"  <file>

but the match do not work !!! Can someone help me ?

Thanks !!!!Smilie
Last edited by vbe; 08-12-2011 at 11:50 AM.. Reason: Do you mind using code tags?
# 2  
Old 08-12-2011
robdcb, I am really having a hard time following the code you pasted; so I am not clear what the intent here is. I was able to do something similar to your description using the following code. Hope this helps.
Code:
BEGIN { b=0 }
{
    if ($0 ~ /LINK \[2\] COUNTERS/)
    {
        a=1
        b=0
    }

    #    After the line matching the pattern is found,
    #    print upto 2 lines following the matching line.

    if (a == 1 && b >= 1 && b < 3)
    {
        print b ":" $0
    } 

    b++
}

You would need to copy these lines into a file and run it with the -f option, BTW.
# 3  
Old 08-12-2011
Hi,

Use 'grep':
Code:
$ cat infile
aaaaaaaaaa                                                                                                                                                                                                                                   
bbbbbbbbb
cccccccccccccccc
dddddddddddd
eeeeeeeeeeee
LINK [2] COUNTERS
ffffffffffffffff
ggggggggggg
hhhhhhhhhhh
iiiiiiiiiii
$ grep -A 3 -F "LINK [2] COUNTERS" infile
LINK [2] COUNTERS
ffffffffffffffff
ggggggggggg
hhhhhhhhhhh

Regards,
Birei
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