How to check existence of variable in csh

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# 1  
Old 07-22-2011
How to check existence of variable in csh

Hi All,

I want to check existence of variable, whose name gets decided dynamically.

E.g. value of this variable,is derived as $option_"exclude" , where value of option varies depending upon user input.

I am trying to do it in a following way :

set exclude_var = `echo $option"_exclude"`
if ( $?$exclude_var ==0 ) then
   echo "Variable not present"

But it gives me error as "Variable Syntax".

Can anyone please explain me where am I going wrong?

# 2  
Old 07-22-2011
==0 should be == 0 ( space between = and 0)
# 3  
Old 07-22-2011
still it is giving same error...
# 4  
Old 07-22-2011
Consider reading this.

I suppose there's a better way (assuming the variable option is always set):

$ set option = ok
$ set ok_exclude = OE
$ eval 'eval if \( \$?${option}_exclude \) echo ok'
$ unset ok_exclude
$ eval 'eval if \( \$?${option}_exclude \) echo ok'

This User Gave Thanks to radoulov For This Post:
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