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searching a sub-string in a string

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Top Forums Shell Programming and Scripting searching a sub-string in a string
# 8  
Old 07-22-2011
Tools Substr
Hi,

Try this one,

Code:
my $newPage = "$simplePage";
my $str = (split("href=\"CVP-LATEST-5.3.0.",$simplePage ))[1];
my $version = substr("$str",0,2);
print "Version: <$version>\n";

I think variable $simplePage doesn't have string data so need to convert to string. Try the above code.i assume href=\"CVP-LATEST-5.3.0. wont change in future.

Cheers,
RangaSmilie
Last edited by radoulov; 07-22-2011 at 07:56 AM.. Reason: Code tags.
# 9  
Old 07-22-2011
Ok, I see some wired behaviour,
Code:
#!/usr/bin/perl
 
use LWP::Simple;
my  $oldversion =36;
 
$pageURL="http://www.google.com/isos/preFCS5.3/LATESTGOODCVP/";   
my $simplePage=get($pageURL);  
 
my $newPage = "$simplePage";
my $str = (split("href=\"CVP-LATEST-5.3.0.",$simplePage ))[1];   //here its again $simplePage or  $newPage ? 
my $version = substr("$str",0,2);
print $version;    // This displays 37  which is correct
 
if($version =! $oldVersion )
{
 
print $version;    // Here it displays 1  which is wrong and so the file dont download.
 
##-- fetch the zip and save it as perlhowto.zip
my $status = getstore("http://www.google.com/isos/preFCS5.3...0.$version.iso", "CVP-LATEST-5.3.0.$version.iso");
}
else
{
print("Currently new version\n");
}

Should I convert the value to integer or something ?
# 10  
Old 07-22-2011
Tools Substr
Quote:
Originally Posted by srijith
Ok, I see some wired behaviour,
Code:
#!/usr/bin/perl
 
use LWP::Simple;
my  $oldversion =36;
 
$pageURL="http://www.google.com/isos/preFCS5.3/LATESTGOODCVP/";   
my $simplePage=get($pageURL);  
 
my $newPage = "$simplePage";
my $str = (split("href=\"CVP-LATEST-5.3.0.",$simplePage ))[1];   //here its again $simplePage or  $newPage ? ==>Its $newPage
my $version = substr("$str",0,2);
print $version;    // This displays 37  which is correct
 
Here take a backup of Variable Version::: 
my $backupVersion = $version; #Takes copy of $version
 
if($version =! $oldVersion )
{
 
print $backupVersion;
print $version;    // Here it displays 1  which is wrong and so the file dont download.
 
##-- fetch the zip and save it as perlhowto.zip
my $status = getstore("http://www.google.com/isos/preFCS5.3...0.$version.iso", "CVP-LATEST-5.3.0.$version.iso");
}
else
{
print("Currently new version\n");
}

Should I convert the value to integer or something ?

Hi,

Make a note on bolded letters.
i think your variable $version overwrites somewhere.

Cheers,
RangaSmilie
# 11  
Old 07-22-2011
Quote:
Originally Posted by rangarasan
Hi,

Make a note on bolded letters.
i think your variable $version overwrites somewhere.

Cheers,
RangaSmilie

Ok, But where is it overwritting ? it can only be in

Code:
if($version =! $oldVersion )

so here its getting changed. But why ?

Also the IF statement is comparing with the new overwritten value.
# 12  
Old 07-22-2011
Tools Substr
Quote:
Originally Posted by srijith
Ok, But where is it overwritting ? it can only be in

Code:
if($version =! $oldVersion )

so here its getting changed. But why ?

Also the IF statement is comparing with the new overwritten value.
Hi,

Look into your comparision Operators.

please make a change as,

if($version != $oldVersion )

Cheers,
RangaSmilie
# 13  
Old 07-22-2011
Quote:
Originally Posted by rangarasan
Hi,

Look into your comparision Operators.

please make a change as,

if($version != $oldVersion )

Cheers,
RangaSmilie

Yes I get it, but whether to use != or ne . Becuase $version is in the form of string and $oldversion is integer.
So eventhough both are equal the IF condition is getting TRUE and the file is downloading.

any idea how to convert to integers ? i tried int() and sprintf both did not work .
Last edited by srijith; 07-22-2011 at 09:15 AM..
# 14  
Old 07-22-2011
Tools Substr
better use != for Numbers.

Cheers
RangaSmilie
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