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Shell Programming and Scripting

can't read the code.

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# 1  
Old 07-22-2011
can't read the code.
Hi All,

I'm a newbie here, can you help me tried to figure out this code. i know that this code is to check the path directory, however when i tried to run the scripts it always says error even though the folder is exist.

Code:
CHECK_PATH_FXN()
{
_CHECK_PATH=$1
if [ ! -d "${_CHECK_PATH}" ]
then
${ECHO_CMD} "ERROR : ${_CHECK_PATH} path is not existing!"
sleep 5
exit
fi
}

Please advise,
Thanks
# 2  
Old 07-22-2011
Code:
 
CHECK_PATH_FXN()
{
_CHECK_PATH=$1
if [ ! -d "${_CHECK_PATH}" ]
then
${ECHO_CMD} "ERROR : ${_CHECK_PATH} path is not existing!"
sleep 5
exit
fi
}

Note : you have ! symbol in the if condition.
# 3  
Old 07-22-2011
Hi Sir,

it says ERROR : path is not existing! even though the path is exist.

Code:
PRODUCT_SCRIPT_NAME=`${BASENAME_CMD} $0`
PRODUCT_NAME_CONV=`${BASENAME_CMD} $0 | ${AWK_CMD} -F".sh" '{print $1}'`
INPUT_PARAM="$1"

CHECK_PATH_FXN()
{
_CHECK_PATH=$1
if [ ! -d "${_CHECK_PATH}" ]
then
${ECHO_CMD} "ERROR : ${_CHECK_PATH} path is not existing!"
sleep 5
exit
fi
}

i don't know if there's something wrong in the $1 which is the input param.

Please advise
Thanks
# 4  
Old 07-22-2011
-d "${_CHECK_PATH}" ----> will return zero (0), if the directory is there
! --- makes the statement as true. ( because 0 is false and other numbers are true in if condition)

just check like this, in the terminal

Code:
 
[ -d /tmp ] && echo $?    # will return zero

Code:
 
[ 0 ] && echo  "if condition" || echo "else condition"
[ 1 ] && echo  "if condition" || echo "else condition"

# 5  
Old 07-22-2011
thank you very much sir, i'm going to try this.

Thanks,
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