Shell Programming and Scripting

Hi,

Try this:

Code:

grep "string1" a.txt | cut -d' ' -f5

@michaelrozar17

Sed version is 4.1.2 of GNU

after using awk command---output file content is-----

spotlight -verilog file.v -$regression -batch -policy=xyz -rules ABC,abc,pqr -wd
ir ../other_files

now i want ABC,abc,pqr only.

it is sure that it will come after -rules but -rules position is not fix in the line so the field can vary for different file so i have to search -rule then extract the next strings till next space.

So Reply me with the suitable solution

Thanks
Manish

---------- Post updated at 05:29 PM ---------- Previous update was at 05:25 PM ----------

@gprashant

Thanks for reply.
i know about this solution.
But problem is string field position is not fix for different file.
so i can not use field operator $5. it may be five in some cases it may be anything.

so i have to search string and then print the next string till the space.

Thanks
MAnish

If the searchd sttring is always "rules" then try this awk liner...

Code:

awk -F- '{for(i=1;i<=NF;i++) if($i~"^rules"){gsub("rules| ","",$i);print $i}}' file

Hi,
Try this:

Code:

sed -n '/WORD1/,/WORD2/p' /path/to/file

Ok. Guess your inputfile has both rules and -rules words..The below given input file is as posted by you.

Code:

$cat infile
Script---

#interpreter
cd directory
spotlight -verilog file.v -$regression -batch -policy=xyz -rules ABC,abc,pqr -wdir ../other_files
cd ...

$sed -n '/-rules/s/.*rules \([^ ]*\) .*/\1/p' infile
ABC,abc,pqr
$sed -n '/-rules/s/.*rules \(.*\) -.*/\1/p' infile
ABC,abc,pqr

Hi Manish,

how about this:

Code:

awk -F"-string1" '{print $2}' a.txt | cut -d" " -f 2 | tail -2 | head -1