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[ask]gate date in different name file

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# 1  
Old 07-02-2011
[ask]gate date in different name file
hlow all,
i have case with different name file tto filter name date only
example file
Code:
BDG.20110627.653212.txt
3GSMG.21.32.20110620.34112.3211.txt
MDN.000.234.123.20110619.2313.3.txt

output
Code:
20110627.txt
20110620.txt
20110619.txt

how can i filtering to get the date if they dinamic position Smilie
any idea for this...

thx for your advice
# 2  
Old 07-02-2011
Try this with GNU sed:

Code:
$ cat >testfile
BDG.20110627.653212.txt
3GSMG.21.32.20110620.34112.3211.txt
MDN.000.234.123.20110619.2313.3.txt
$ sed -r 's/.*\.(20[0-9]{6})\..*/\1.txt/' testfile
20110627.txt
20110620.txt
20110619.txt

Last edited by yazu; 07-02-2011 at 02:05 AM.. Reason: more robust
This User Gave Thanks to yazu For This Post:
zvtral
# 3  
Old 07-02-2011
@yazu thx for your replay
but in case not include in file if I ls have thist
Code:
# ls
BDG.20110627.653212.txt
3GSMG.21.32.20110620.34112.3211.txt
MDN.000.234.123.20110619.2313.3.txt

so i want get file like this
Code:
#ls
20110627.txt
20110620.txt
20110619.txt

anyway have sed compile with
Code:
find -name *.txt*|sed -r 's/.*\.(20[0-9]{6})\..*/\

any advice????
Last edited by zvtral; 07-02-2011 at 02:30 AM..
# 4  
Old 07-04-2011
hlow there

any can help me about this case???
input
Code:
# ls
BDG.20110627.653212.txt
3GSMG.21.32.20110620.34112.3211.txt
MDN.000.234.123.20110619.2313.3.txt

output
Code:
#ls
20110627.txt
20110620.txt
20110619.txt

with awk
Last edited by zvtral; 07-04-2011 at 11:28 AM..
# 5  
Old 07-04-2011
Code:
ls | sed 's/.*\([0-9]\{8\}\).*/\1.txt/'

Code:
for i in *
do
mv $i $(echo $i | sed 's/.*\([0-9]\{8\}\).*/\1.txt/')
done

This User Gave Thanks to ctsgnb For This Post:
zvtral
# 6  
Old 07-04-2011
Quote:
Originally Posted by ctsgnb
Code:
ls | sed 's/.*\([0-9]\{8\}\).*/\1.txt/'

Code:
for i in *
do
mv $i $(echo $i | sed 's/.*\([0-9]\{8\}\).*/\1.txt/')
done

wow its a great yhx men for helping meSmilie
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