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Shell scripting newbie problem


 
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# 1  
Old 06-05-2011
Shell scripting newbie problem

I am trying to create a shell script similar to ls, but which only lists directories. I have the first half working (no argument version), but trying to make it accept an argument, I am failing. My logic is sound I think, but I'm missing something on the syntax, I'm guessing in the bolded line? Any help would be greatly appreciated, thanks!

Code:
if [ $# -eq 0 ] ; then
    d=`pwd`
    for i in * ; do
        if test -d $d/$i ; then
            echo "$i:"
        fi
    done
else
    if [ $# -eq 1 ] ; then
        d=$1
        for i in * ; do
            if test -d $d/$i ; then
                echo "$i:"
            fi
        done
    fi
fi

# 2  
Old 06-05-2011
Code:
ls -l |grep ^d

find . -type d

# 3  
Old 06-05-2011
rdc, I know there are probably better tools, but this is an assignment I'm stuck with. :-/

Thanks for the quick reply though!

Last edited by Tibor63; 06-05-2011 at 11:50 PM..
# 4  
Old 06-06-2011
are you passing the absolute path as argument ?

what error you are getting ?
# 5  
Old 06-06-2011
No, I'm not passing the absolute path, just the same type of argument you'd pass "ls" for example.

I've tried using "~" "/" and "..." as arguments... I think I even tried the absolute path once (but can't remember for sure).
# 6  
Old 06-06-2011
If you want to check the passed argument is a directory or not by using

Code:
if test -d $1 ; then
     echo "$i:"
fi

Code:
[ -d $1 ] && echo "$1 is directory" || echo "$1 is not directory"

# 7  
Old 06-06-2011
Quote:
Originally Posted by itkamaraj
If you want to check the passed argument is a directory or not by using
No, the goal is to check if the contents (of the argument directory) are directories or not. I got it working with this code below, but what I don't understand is why the for/if notation I used in the top (no argument version) had to be changed so much for the bottom (argument version). I guess I'm not sure exactly what "i in *" (in the top version) is iterating over. How does it define *?

Code:
if [ $# -eq 0 ] ; then
    d=`pwd`
    for i in * ; do
        if test -d "$d"/"$i" ; then
            echo "$i:"
        fi
    done
else
    if [ $# -eq 1 ] ; then
        d="$1"
        for i in "$d"/* ; do
            if test -d "$i" ; then
                echo "${i##*/}:"
            fi
        done
    fi
fi


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