Shell Programming and Scripting

Hi All,

Am a Beginner to shell scripting, so please pardon my question.

Below is the file format of file a.txt

a.txt

Code:

F=3
a|b|c|d
1|2|3|4
as|as|asd|asd
Aas|as|asd|ada

In the above file format, i have record count of total no of records excluding the header file here 3 , this varies depending upon the no of records in the file.

I am using the below in command mode .

Code:

head -1 a.txt | cut -c 3-

and am getting the output correctly which is 3.

How ever when i put the same above command in shell script, am not getting the correct answer .

Below is the script

Code:

#!/bin/ksh
count=`head -1 a.txt | cut -c 3-`
echo $count

Am getting the variable count displayed as $'3\r' , Can anyone please help me if am missing something here obvious.

I cant process the downstream program, because of this issue.

Thanks for looking into the issue.

Your source file is in DOS format (CR-LF) instead of Unix format (LF ending).
One workaround would be:

Code:

 count=$(head -1 a.txt | dos2unix | cut -c 3-)

Very Thanks jlliagre , it works like Magic...it is indeed copied over from windows.