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Use $var within quotes

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# 1  
Old 04-28-2011
Use $var within quotes
Hi all,

My code reads:

Code:
foldername=$(basename $PWD)
myvar=$(rm -v `ls | grep -vE 'file1|file2|$foldername.ext'` | wc -l)
echo "Removed $myvar files"

The thing is $foldername won't pick the value stored in 'foldername'. My guess is that the single-quotes are making it read $foldername literally. Any suggestions?
# 2  
Old 04-28-2011
Use double quotes, single quotes prevent the shell to expand the variable:
Code:
myvar=$(rm -v $(ls | grep -vE "file1|file2|$foldername.ext") | wc -l)

# 3  
Old 04-28-2011
Thanks. I was trying using brackets instead, bad idea.
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