Shell Programming and Scripting

If you you want to print only first occurance then you can use exit.

Code:

awk -v k="567889" '/^GS/{p=NR}$0~"^RMR.*\\*"k{f=1}/^GE/&&f{printf("%d %d\n",p,NR);f=0;exit}' input file

So RMR will be a unique number always?
But GS will not be unique. Is this what you mean?

Following is valid right
GS*12345***** ST*1******** A* B* E* RMR*123455(This is the unique number to locate this row) F* SE*1*** GE*12345*
GS*12345***** ST*1******** A* B* E* RMR*7689(This is the unique number to locate this row) F* SE*1*** GE*12345*

Also, can you paste the error you are getting when you executed the awk command?
btw which OS are you using and shell?

regards,
Ahamed

No it cannot be the 1st occurrence, it should be based on the comboination of the unique number in GS* row and the account number if RMR*. Read my first post for the details. Hope that will explain you..

Thanks for your time on this

---------- Post updated at 05:36 AM ---------- Previous update was at 04:54 AM ----------

GS* will be an unique number and RMR*account number can be the same and that can occur in different GS-GE loop

I am using /bin/ksh and HP-UX. I have posted the error in my previous post.

---------- Post updated at 07:00 AM ---------- Previous update was at 05:36 AM ----------

Can someone help me with this issue..