Hello, first off, let me begin by saying that I am a complete GNU/linux noob. I installed it on my laptop not even a month ago, because I've gotten tired of Windows on my laptop, but anyway. I'm starting to write bash shell scripts, and one of my friends who found out that I was starting this and never had any luck with shell scripts said that their memcache is always full after running a virtual machine, or just leaving it active for a while. So I figured that the best way to solve this would be to write a script (because there's no simple pre-existing command to do this that I've found on the internet), my problem is that every time I try to run it, I get the following error:
Code:
./clrcache: line 36: syntax error near unexpected token `elif'
./clrcache: line 36: ` elif [ "$#" == 0 ]; then'
I already know that the cache dumping mechanism in the code works, because I've tested it in its own separate script. I've also tested the switching mechanism. the following is the entire script, as well as a comment where the issue is, so that you don't need to count.
Code:
#! /bin/bash
### BEGIN INIT INFO
# Provides: Simple method of clearing cache
# Required-Start:
# Required-Stop:
# Default-Start:
# Default-Stop:
# Short-Description: Drops the cache like it's hot.
### END INIT INFO
if [ "$1" == "-?" || "$1" == "--?" || "$1" == "-help" || "$1" == "--help" && "$#" == 1 ]; then
echo "Usage: $0 [arguments]" \n \n
echo "Valid arguments:" \n
echo "-fy Forces a yes option, implies -nw."\n
echo "-nw Shows no warning, however, will still ask if you really want to clear the cache" \n
echo "-?, --?, -help, --help all display this page." \n \n
echo "$0 is a small program designed to dump the cache that can hog up space in the RAM of a system," \n
echo "it is not recommended for use on a machine with multiple clients, or virtual machines, such as servers."
exit 0
elif [ "$1" == "-fy" && "$#" == 1 ]; then
sync #Dumps the cache into non-volitile storage
sudo echo "$2" | sudo tee /proc/sys/vm/drop_caches #removes the cache from the RAM
exit 0
elif [ "$1" == "-nw" && "$1" != "-fy" && "$#" == 1 ]; then
OPTIONS="Continue Stop"
select opt in $OPTIONS; do
if [ "$opt" == "Continue" ]; then
sync #Dumps the cache into non-volitile storage
sudo echo done | sudo tee /proc/sys/vm/drop_caches #removes the cache from the RAM
exit 0
elif [ "$opt" == "Stop" ]; then
echo "Did not remove cache from RAM"
exit 0
else
echo "bad option"
exit 0
fi
elif [ "$#" == 0 ]; then #THIS IS THE LINE THAT THE TERMINAL HAS A PROBLEM WITH!!!!!!!!!!!!!!!!!!!!!!!!!!!!
echo "WARNING: This script is designed to dump the cache from the system's memory." \n
echo "This may cause issues with certain files, especially those in virtual machines." \n
echo "If you still wish to continue, please make sure all files have been saved." \n
OPTIONS="Continue Stop"
select opt in $OPTIONS; do
if [ "$opt" == "Continue" ]; then
sync #Dumps the cache into non-volitile storage
sudo echo done | sudo tee /proc/sys/vm/drop_caches #removes the cache from the RAM
exit 0
elif [ "$opt" == "Stop" ]; then
echo "Did not remove cache from RAM"
exit 0
else
echo "bad option"
fi
else
echo "I'm not sure what you did, but you managed to break it, good job, you're a winner."
exit 0
fi
exit 0
For those of you who noticed, it can also take arguments, however, every time I've tried to invoke them, the same error occurs, at the same line. Any help would be greatly appreciated, thank you!
Last edited by Puddles187; 04-09-2011 at 11:23 PM..
Reason: page spacing, grammatical errors.
After replacing some &&s with -a, the terminal said that that invoked another syntax error around the areas that I changed them. Right now, I'm not all that concerned about what an echo statement says so much as getting my code to build and run... Thanks for the pointers, though!
Thank you all for your input, I've changed == to = and -eq where you suggested, however, the fact still remains that so far this is NOT a problem with logic, so much as it IS a problem with syntax around ONE SPECIFIC IF STATEMENT
Code:
#! /bin/bash
#switch test
OPTIONS="Continue Stop"
select opt in $OPTIONS; do
if [ "$opt" = "Continue" ]; then
sync #Dumps the cache into non-volitile storage
sudo echo done | sudo tee /proc/sys/vm/drop_caches #removes the cache from the RAM
exit 0
elif [ "$opt" = "Stop" ]; then
echo "Did not remove cache from RAM"
exit 0
else
echo "bad option"
exit 0
done
fi
Is the problem segment right now. In fact, if this code alone, with no other logic arguments were to be entered, it would still produce the same error (but in a different numbered line)
Code:
./Switch-test: line 15: syntax error near unexpected token `done'
./Switch-test: line 15: ` done'
Even if I were to put the "exit 0" commands outside of the if statement, it still returns with the same error. So, the problem is in the if statement, and not the logic. Could you please help me with this if statement? Seeing as the main one runs well enough so far.
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