Thank you all for your input, I've changed == to = and -eq where you suggested, however, the fact still remains that so far this is NOT a problem with logic, so much as it IS a problem with syntax around ONE SPECIFIC IF STATEMENT

Code:

#! /bin/bash
#switch test
OPTIONS="Continue Stop"
    select opt in $OPTIONS; do
        if [ "$opt" = "Continue" ]; then
            sync #Dumps the cache into non-volitile storage
            sudo echo done | sudo tee /proc/sys/vm/drop_caches #removes the cache from the RAM
                    exit 0
        elif [ "$opt" = "Stop" ]; then
                    echo "Did not remove cache from RAM"
            exit 0
        else
                    echo "bad option"
            exit 0
        done
                fi

Is the problem segment right now. In fact, if this code alone, with no other logic arguments were to be entered, it would still produce the same error (but in a different numbered line)

Code:

./Switch-test: line 15: syntax error near unexpected token `done'
./Switch-test: line 15: `        done'

Even if I were to put the "exit 0" commands outside of the if statement, it still returns with the same error. So, the problem is in the if statement, and not the logic. Could you please help me with this if statement? Seeing as the main one runs well enough so far.