Shell Programming and Scripting

Hi,

can someone point out a solution to my problem below.

Within a shell script TEST.ksh I have to run two commands CmdA & CmdB one after the other as below.
-------------
TEST.ksh
#!/usr/bin/ksh
A
B
-------------

I am running this script from KSH with PID 12345 as below.

./TEST.ksh

But the command A is such that it gets launched in a new shell altogether, i.e. say with PID 56789. Now since A command has launched a new shell the command B doesn't get started untill I go and manually kill the KSH shell that A got started in, or just do an 'exit' from the current shell where I ran the TEST.ksh script.

Is there a way to run both A & B from a single script and without having to manually kill/exit the shell ???

One more thing to note here is that B has to run in the same shell as A as there is a dependancy of B on A.

Thanks,
Krishna

I'm starting to feel like a broken record here.

We are not psychic specialists. Please post your actual, complete code. Without that we can't tell the real source of the problem -- why A isn't completing like it should.

Thanks for the reply. here is the code.

-----------------------------

Code:

#!/usr/bin/ksh

Load clearcase
cleartool setview j999999
$HOME/test.ksh

-----------------------------

The cleartool command gets launched in a new shell and the control doesn't go to the test.ksh untill I exit from current shell. I wanted to know if I can run test.ksh as well in the same shell that cleartool runs in ?

Also just to demonstrate the behaviour or the cleartool command I ran it from command prompt for your reference.

Code:

> ps|grep $$
13727 pts/57   0:00 ksh
> cleartool setview j965155_edg
> ps|grep $$
21081 pts/57   0:00 ksh

Google is your friend.

See if this works for you:

Code:

{ cleartool setview j999999 ; $HOME/test.ksh ; }

Thanks Guys, it worked for me !!!!