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bash script directory size

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# 1  
Old 03-23-2011
bash script directory size
hello!

i need to make a script that get a folder name in parameter and i get back the size of the folder include the subfolders! but i dont know how i need to start :S

Example:
a folder contain the followings
Code:
a:
drwxr-xr-x 2 user user 4096 febr 25 08.27 b
-rw-r--r-- 1 user user 2 febr 24 14.29 valami.txt

there is a b folder in the a folder that contains these:
Code:
-rw-r--r-- 1 user user 63206 febr 24 14.29 en3700.pdf
-rw-r--r-- 1 user user 20532 febr 24 14.29 info_bucsu.odt
-rw-r--r-- 1 user user 2 febr 24 14.29 más.txt

and the script have to work like that: i have give the Folder name as parameter to the script and that give back the size of the folder(s).
Code:
$ ./sum.sh a
83742

thx the help
Last edited by Scott; 03-23-2011 at 06:14 PM.. Reason: Please use code tags
# 2  
Old 03-23-2011
You don't need a script for that at all.

Code:
du -s foldername

will sum up the size of the folder and things inside it, reporting in 512-byte blocks. If you want it to report in human-readable numbers, add -h.

Note that it's disk used, which can be subtly different from the precise byte count of all the files but is a more accurate reflection of its actual disk footprint.
# 3  
Old 03-23-2011
that is my script:
Code:
#!/bin/bash

DIRSIZE=`du -bs $1 | cut -f 1`

echo $DIRSIZE

Code:
~$ ls -lR h867879
h867879:

Summary: 8

-rw-r--r-- 1 h867879 hallgato 536 2011-03-23 17:14 h867879.sh

h867879@linux4:~$ bash kotprog2.sh h867879
4400

and 536 not equal with 4400 :S
Last edited by Scott; 03-23-2011 at 06:15 PM.. Reason: Code tags
# 4  
Old 03-24-2011
Quote:
Originally Posted by Corona688
Note that it's disk used, which can be subtly different from the precise byte count of all the files but is a more accurate reflection of its actual disk footprint.
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