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display number of days in current month

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# 8  
Old 03-15-2011
wow thanks guys
# 9  
Old 03-15-2011
hehehe, so many ways to skin a cat.

@ctsgnb, thanks was my sed solution - fix was pretty simple:
Code:
# cal 7 2011 | sed -n '/[23]/h;${x;s/.* //;p}'
31

# 10  
Old 03-15-2011
Hehe yes,

@Schubler,

Your fix works on linux... but it requires an additional little semicolon fix to work on the solaris 10 i have tryied (i think FreeBSD has the same kind of need of ending semicolon before "}" ... so in fact better to keep both of the semicolon before and after the p

Code:
$ uname -a
SunOS xxxxxx 5.10 Generic_141414-01 sun4u sparc SUNW,Sun-Fire-V490
$ cal 7 2011 | sed -n '/[23]/h;${x;s/.* //;p}'
sed: command garbled: /[23]/h;${x;s/.* //;p}
$ cal 7 2011 | sed -n '/[23]/h;${x;s/.* //;p;}'
31
$

another one for the fun ...
Code:
$ echo $(cal) | tail -c 3
31

or if running solaris
Code:
$ echo $(cal) | /usr/xpg4/bin/tail -c 3
31

Last edited by ctsgnb; 03-15-2011 at 09:36 PM..
# 11  
Old 03-15-2011
Using FreeBSD Man Page for date (FreeBSD Section 0) - The UNIX and Linux Forums
Code:
# uname
FreeBSD
# date
Tue Mar 15 21:05:40 EDT 2011
# date -v 1d -v +1m  -v -1d "+%A %B %d %Y"                           # First day of (current month+1) minus 1 day.
Thursday March 31 2011
# date -v 1d -v +1m  -v -1d "+%d"
31
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