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Copy a file with backslash in the filename

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# 1  
Old 03-15-2011
Copy a file with backslash in the filename
Hi,

I'm trying to make a script that copy a file that has a backslash in the filename.

What I'm doing wrong?

The flename is: 1300212744.H786972P30819.ns1.cybernet.com.br,S\=6313:2,

My script
Code:
ParteA="1300212970.H27173P31627.ns1.cybernet.com.br,S"
ParteB=\\
ParteC="="
ParteZ=":2,"
Y=6301

Y=$(( $Y + 1 ))
ARQ1="111300212970.H27173P31627.ns1.cybernet.com.br,S\\=6301:2,"

 ARQ2=$ParteA$ParteB$ParteB$ParteC$Y$ParteZ

 echo " "
 echo "ARQ1: " $ARQ1
 echo "ARQ2: " $ARQ2
 echo "ParteB: " $ParteB

  cp $ARQ1 $ARQ2


Regards and thanks for any help,

Ronaldo
Last edited by Franklin52; 03-16-2011 at 06:26 AM.. Reason: Please use code tags
# 2  
Old 03-15-2011
Your script works fine for me:

Code:
$ ls
111300212970.H27173P31627.ns1.cybernet.com.br,S\=6301:2,
myscript
$ ./myscript
 
ARQ1:  111300212970.H27173P31627.ns1.cybernet.com.br,S\=6301:2,
ARQ2:  1300212970.H27173P31627.ns1.cybernet.com.br,S\\=6302:2,
ParteB:  \
$ ls
111300212970.H27173P31627.ns1.cybernet.com.br,S\=6301:2,
1300212970.H27173P31627.ns1.cybernet.com.br,S\\=6302:2,
myscript

If you dont want double \ in the outfile name take 2nd parteB out (i.e. remove code in red below):
Code:
ARQ2=$ParteA$ParteB$ParteB$ParteC$Y$ParteZ

Also note: these filenames won't work on cygwin as MSDOS uses \ as a directory separator and so disallows this character for filenames. commas and colons also cause issues for some shells - you should consider excaping them too.
Last edited by Chubler_XL; 03-15-2011 at 07:10 PM..
# 3  
Old 03-15-2011
This may depend on the shell...
What kind of shell are you using?

But jeez, what an ugly filename. Don't you want to rename it to something less troublesome? You can always grab it by inode and rename it that way:
Code:
$ ls -i 300212744.H786972P30819.ns1.cybernet.com.br\,S\=6313\:2\, 
9994367 300212744.H786972P30819.ns1.cybernet.com.br,S=6313:2,
$ find . -inum 9994367 -exec mv {} someReasonableName \;
$ ls
someReasonableName

# 4  
Old 03-15-2011
Thanks for your answer,

The filename are generated by the unix, born shell, CentOS, and I need the copy to make jounally file backups.

---------- Post updated at 07:14 PM ---------- Previous update was at 07:10 PM ----------

Chubler,

Thanks for your answer, but if you saw the second ls command, we have two \\ (backslash) instead the one from the original filename.

$ ls
111300212970.H27173P31627.ns1.cybernet.com.br,S\=6301:2,
myscript
$ ./myscript

ARQ1: 111300212970.H27173P31627.ns1.cybernet.com.br,S\=6301:2,
ARQ2: 1300212970.H27173P31627.ns1.cybernet.com.br,S\\=6302:2,
ParteB: \
$ ls
111300212970.H27173P31627.ns1.cybernet.com.br,S\=6301:2,
1300212970.H27173P31627.ns1.cybernet.com.br,S\\=6302:2,
myscript

I need to maintain the filename, changing only the sequence number, that I increment on each copy.

That is my great problem, I can't generate the output filename with only one backslash.

Thanks again,

Ronaldo
# 5  
Old 03-15-2011
OK. I am running bash on CentOS also. It seems to be working fine on my machine. What exactly is your problem? Error message? Does the copying happen with a bad filename or it doesn't copy at all?

One good practice is to use braces when concatenating vars, like:
Code:
ARQ2=${ParteA}${ParteB}${ParteB}

You end up with two backslashes because you have $ParteB twice in that concat. So your ARQ2 has 2 backslashes.

Might be easier to use sed for substitution:

Code:
old=`echo $file | awk -F= '{print $2}' | awk -F: '{print $1}'`
new=$((old+1)); 

newname=`echo file  | sed "s/=$old:/=$new:/"`
cp $file $newname

the '=' and ':' in sed patterns kept so that you don't replace the number in the first part of filename.
Last edited by mirni; 03-15-2011 at 07:26 PM..
# 6  
Old 03-15-2011
Thanks,

But if I use only one backslash, the shell interpret the backslash ans ommit it.

Thats my problem, I can't generate the output filename correct, with only one slash and the number sequence incremented.

Regards,

Ronaldo
# 7  
Old 03-15-2011
Code:
$ ls
111300212970.H27173P31627.ns1.cybernet.com.br,S\=6301:2,  test.sh
$ cat test.sh 
#!/bin/bash


ParteA="1300212970.H27173P31627.ns1.cybernet.com.br,S"
ParteB=\\
ParteC="="
ParteZ=":2,"
Y=6301

Y=$(( $Y + 1 ))
ARQ1="111300212970.H27173P31627.ns1.cybernet.com.br,S\\=6301:2,"

ARQ2=$ParteA$ParteB$ParteC$Y$ParteZ

echo " "
echo "ARQ1: " $ARQ1
echo "ARQ2: " $ARQ2
echo "ParteB: " $ParteB

cp $ARQ1 $ARQ2

$ ./test.sh 
 
ARQ1:  111300212970.H27173P31627.ns1.cybernet.com.br,S\=6301:2,
ARQ2:  1300212970.H27173P31627.ns1.cybernet.com.br,S\=6302:2,
ParteB:  \
$ ls
111300212970.H27173P31627.ns1.cybernet.com.br,S\=6301:2,  test.sh
1300212970.H27173P31627.ns1.cybernet.com.br,S\=6302:2,

Seems to work fine when I took the second $ParteB out...

But what may help is if you quote the vars in cp command:
Code:
cp "$ARQ1" "$ARQ2"
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