10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Team,
Got a thousand servers. I created a script to say hello on every server. But is there a script or whatever that will issue a yes on every key checking.
for i in `cat myserverlist`
do
echo $i
ssh-copy-id $i
done
The authenticity of host 'server1 (162.162.0.10)' can't be... (7 Replies)
Discussion started by: invinzin21
7 Replies
2. Shell Programming and Scripting
Hi,
This is a script which to create an opvn user, I want which answer automatically to a certain part so, I try this, it works without the red part but I must type manually.. :
#!/bin/bash
## Environnement ##
LC_ALL=C
## Paths ##
rsa_dir="etc/openvpn/easy-rsa"... (10 Replies)
Discussion started by: Arnaudh78
10 Replies
3. Shell Programming and Scripting
I am looking for a way to start a script and have it prompt for a password that will be used later on in the script to SSH to another host and to SFTP. I don't want the password to be hard coded. Below is my script with the actual IP's and usernames removed.
#!/usr/bin/expect -f... (2 Replies)
Discussion started by: jbrass
2 Replies
4. Shell Programming and Scripting
Hi
I'm working with AIX 6.1
I would like to ssh to a server without entering password ( to monitor something) but there's no way to do that by authentication keys, so I need to write a script which can ssh to that server without entering password ( no need to hide passsword in the script, just an... (9 Replies)
Discussion started by: bobochacha29
9 Replies
5. Shell Programming and Scripting
I have a shell script to run set of commands every week . I dont have a root access on the server but I can run the commands using pbrun
cat myscript.sh
*
*
*
pbrun command....
each time I run the script , it asks me for my password then it executes fine.
./myscript.sh
Password... (7 Replies)
Discussion started by: Sara_84
7 Replies
6. UNIX for Dummies Questions & Answers
In the script i am passing a command from script which is called from cron. When this command is called from cron the unix prompt asks for password. Can we automatically enter the password when promted(if the password is hardcoded in script)??
Please let me know how to enter the password... (4 Replies)
Discussion started by: abhi_n123
4 Replies
7. Shell Programming and Scripting
I'm using rsync with the "-e ssh" option so of course it asks for a password using a prompt. Is there a way to tell a script to expect a prompt, wait for it, and give a password when it arrives?
There is a way to give rsync a password as part of its options using a file, but it only works with... (2 Replies)
Discussion started by: davidstvz
2 Replies
8. Shell Programming and Scripting
Hi Friends,
We need to create a script which will invoke a command with diffrent parameters.
The command invoked needs the password. So how automatically we can enter password in the script to the command?
example.:
#!/bin/ksh
for par in `cat parfile` do
# Here is the main command... (1 Reply)
Discussion started by: sourabhsharma
1 Replies
9. Shell Programming and Scripting
I want to write a script which will automatically take password
sequentially from a file after every 10 days.
i.e the passwd command should be executed automatically every 10 days and it should take the input from the password file sequentially.
Has any1 got a solution?????????????? (1 Reply)
Discussion started by: rahulrathod
1 Replies
10. UNIX for Dummies Questions & Answers
I would like to create a script that logs into a list of several servers 50+ and changes my password all at once.
Every 60 days we are required to login to each system and change our passwords or else they expire and our login account is deleted.
I have an idea on how I could do this but... (4 Replies)
Discussion started by: darthur
4 Replies
bup-margin(1) General Commands Manual bup-margin(1)
NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS
--predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO
bup-midx(1), bup-save(1)
BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown- bup-margin(1)