Shell Programming and Scripting

Hi All,

I have a file with contents :

Code:

cat >file1.sh
qw^A34^Aer

the command i am using is:

Code:

cut -f1,2,3 -d"^A" file1.sh

which gave output as:

Code:

qw^A34^Aer

and the command

Code:

cut -f2 -d"^A" file1.sh

gave an output :

Code:

A34

i need the output as :

Code:

34

Please give suggestions as to how can i get the desired output.
Thanks in advance.

Regards,
Sandhya

Could you post the output of the following command:

Code:

od -cb file1.sh

I'll post the output you sent me in private:

But now we're able to solve it by providing the proper solution:

Code:

awk -F'\\^A' '{ print $2 }' file1.sh

cut doesn't support multi-character delimiters ...

@sed11awk11:

thnks a lot for replyng ...but my input data can have character 'A' in it..

@radoulov

thnks a lot for the reply ...it solved my query...

---------- Post updated 01-06-11 at 12:57 AM ---------- Previous update was 01-05-11 at 09:12 AM ----------

hi,

the command given by radoulov is working while i am using it in command prompt but when i try to use it in a script it is giving me some erronous output...can you suggest a way out of this..

Code:

more file1.sh
qw^A34^Aer

Code:

awk -F'\\^A' '{ print $1 }' file1.sh
qw

this i had used inside a script:

Code:

export a=`awk -F'\\^A' '{ print $1 }' file1.sh`

resulted in :

Code:

$ echo $a
qw^A34^Aer

below is just a work-around.. Not sure why back-ticks behaves this way.(may be the shell your are running creates this ..?)

Code:

export a=$(awk -F'\\^A' '{ print $1 }' file1.sh)

hi michael,

thanks for the sol..it wrkd...