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Printing several lines of a file after a specific expression

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# 1  
Old 01-04-2011
Printing several lines of a file after a specific expression
Hello,

I want to print a number of lines of a file after a specific expression of a line.
I have this sed command but it prints only 1 line after the expression.
How could I adapt it to print for instance 10 lines after or 15 lines after ?

Code:
sed -n '/regexp/{n;p;}'

Thx & Regs,
Rany.
# 2  
Old 01-04-2011
Some examples
https://www.unix.com/shell-programmin...fter-grep.html
sed command to print lines after expression
https://www.unix.com/shell-programmin...ter-regex.html
# 3  
Old 01-04-2011
Have you tried grep -A and grep -B?
# 4  
Old 01-04-2011
Thx a lot for your replies.

I tried this solution but it displays always the expression line number as a first line, what can I do to not print this first line in output ?

Code:
 
$ nawk 'c&&c--;/aaa/{print NR;c=3}' ttt2                
2
1
2
3

$ cat ttt2
0
aaa
1
2
3
4
5
6
7
8
9
10

Regs,
Rany.
# 5  
Old 01-04-2011
Code:
awk 'c&&c--;/aaa/{c=3}' tt2

# 6  
Old 01-04-2011
Perfect ...
Thx a lot.
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