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Simplify Bash Script Using "sed" Or "awk"

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# 1  
Old 12-02-2010
Simplify Bash Script Using "sed" Or "awk"
Input file:

PHP Code:
2 aux003.net3.com error12
6 awn0117.net1.com error13
84 aux008 error14
29 aux001.ha.ux.isd.com error12
209 aux002.vm.ux.isd.com error34
21 alx0027.vm.net2.com error12
227 dux001.net5.com error123
22 us008.dot.net2.com error121
13 us009.net2.com error129 
Expected Output:
PHP Code:
2 aux003 error12
6 awn0117 error13
84 aux008 error14
29 aux001 error12
209 aux002 error34
21 alx0027 error12
227 dux001 error123
22 us008 error121
13 us009 error129 
For now i used this:
Code:
sed -e 's/.net[1-5].com//' -e 's/.ha.ux.isd.com//'

But its not applicable for all domains, i have to put new -e on each domain.
How do we simplyfy this, so i can remove all the FQDN and just remain the hostname?
Last edited by Scott; 12-02-2010 at 05:39 AM.. Reason: One more code tag
# 2  
Old 12-02-2010
Try:
Code:
sed 's/\.[^ \t]*//'

# 3  
Old 12-02-2010
try if this helps..
Code:
sed 's/\.[^ ]*//' inputfile > outfile

# 4  
Old 12-02-2010
wow, it works like charm:

PHP Code:
# sed 's/\.[^ ]*//' /tmp/testerr.out
2 aux003 error12
6 awn0117 error13
84 aux008 error14
29 aux001 error12
209 aux002 error34
21 alx0027 error12
227 dux001 error123
22 us008 error121
13 us009 error129 
Thanks a lot guys
# 5  
Old 12-02-2010
Code:
awk -F'[. ]' '{print $1,$2,$NF}' file

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