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please check this code

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Top Forums Shell Programming and Scripting please check this code
# 1  
Old 11-17-2010
please check this code
hi,
i m checking the directory is empty or not

Code:
  FILE=""
  DIR="/ann/a1"

if [ "$(ls -A $dir)" ]; then
       echo "$dir is not Empty"
  else
      echo "$dir is Empty"
  fi

i m always getting this directory is not empty, even if the directory is empty



please point where i had went wrong??
# 2  
Old 11-17-2010
FILE=""
DIR="/ann/a1"

if [ -z "$(ls -A $DIR)" ]; then
echo "$dir is not Empty"
else
echo "$dir is Empty"
fi
# 3  
Old 11-17-2010
hi ,
now im getting only dir is empty.... for what ever condition.....



when ever i had cehcked this line ls -A $dir
its giving me the error like this directory not accessible Smilie


regards
Angel
# 4  
Old 11-17-2010
Couple of issues here.
1) Environment Variable names are case-sensitive. $DIR and $dir are not the same variable.
2) Your messages appear to be the wrong way round. When we find no files (and the -z condition is satisfied) our message should be "Empty".

Code:
FILE=""
dir="/ann/a1"

if [ -z "$(ls $dir)" ]; then
     echo "$dir is Empty"
else
     echo "$dir is not Empty"
fi

This User Gave Thanks to methyl For This Post:
anurag.singh
# 5  
Old 11-17-2010
Quote:
Originally Posted by methyl
Code:
FILE=""
dir="/ann/a1"

if [ -z "$(ls $dir)" ]; then
else
     echo "$dir is not Empty"
fi

There's no need of process substitution : (just take care that the condition is reverted)
Code:
dir="/ann/a1"
if ls $dir; then
     echo "$dir is not Empty"
else
     echo "$dir is Empty"
fi

# 6  
Old 11-17-2010
Quote:
Originally Posted by anurag.singh
FILE=""
DIR="/ann/a1"

if [ -z "$(ls -A $DIR)" ]; then
echo "$dir is not Empty"
else
echo "$dir is Empty"
fi
This is wrong : -z is true if empty
so... it should be

Code:
if [ -z "$(ls -A $DIR)" ]; then
echo "$dir IS Empty"
else
echo "$dir is NOT Empty"
fi

or

Code:
if [ -n "$(ls -A $DIR)" ]; then
echo "$dir is not Empty"
else
echo "$dir is Empty"
fi

# 7  
Old 11-17-2010
Code:
emptydir() { set -- "$1"/*; ! [ -e "$1" ] ;}
if emptydir "$DIR"; then
  echo "dir is Empty"
else
  echo "dir is not Empty"
fi

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