Shell Programming and Scripting

Thanks alot panyam..Its working fine..

---------- Post updated at 07:12 AM ---------- Previous update was at 06:58 AM ----------

Hey Panyam,

Could you please explain me the above code. It will be very helpful for me.

Thanks,

awk '/^$/ {p=1;q="";next} /insert/ {q=$0;next} q { print q;q=""} 1' input_file

1. /^$/ --> Empty line go to next

2. /insert/ --> have insert in the line , store the line in "q" and go to next line

3. if "q" is not empty print it and make "q" empty.

for your input ,

Code:

 
 
insert_job: fsetlbqafswW999spacereport job_type: c

First line is blank , so step (1) is matched , hence will go to next line
For second line ,step(2) is matched , since the line have "insert" in to. so store it in "q' and go to next line
For third line , agian it's blank , so step(1) will be matched and will make "q" empty and go to next line.

Regards
Ravi

Thanks alot Ravi. That clears my doubt.