Hi guys, I use this function which was provided to me by someone at this site. It works perfectly for validating a users input option against allowed options..
example:
validateInput "1" "1 3 4 5" would return 0 (success)
but now we allow users to enter more than 1 number and so this validate needs to be improved
validateInput "16" "1 3 4 5" this should return fail (1) as 6 is not in the allowedInput string.. currently the function return success because "1" is in the allowedInput string.. but I somehow need it to verify all the numbers in the first parameter
validateInput "16" "1 3 4 5" this should return fail (1) as 6 is not in the allowedInput string.. currently the function return success because "1" is in the allowedInput string.. but I somehow need it to verify all the numbers in the first parameter
Gents,
I did the below code to get an output (report) ,.. the code works fine but I believe it can be more shorted using better method.
Please if you can help, to generate same output improving the code , will be great.
here my code.
# get diff in time
awk '{$9=$8-prev8;prev8=$8;print... (8 Replies)
Thank you for taking the time to look at this and provide input.
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