Shell Programming and Scripting

I have a file that contains the following multiple times:

Code:

0<<
bla bla bla
bla bla bla
exit;

Can somebody give me a sed or AWK command I can use to remove all
occurances from this file.

I would like it to find 0<< (note the zero may be proceeded by spaces) and remove that line and the other 3 lines directly under it.

Thanks in advance to all who answer.

Code:

nawk '/^ *0<</ {n=5}; n && --n{next}1' myFile

Thanks for the help. Just curious, why nawk and not awk is this statement not portable amongst different flavors of UNIX (ie Solaris, AIX, HPUX).

I also like to know if I got understand your code. I get the matching part.
The second part, is because I have four lines to delete you set your varable n=5, decrement it and delete a line at a time?

Very eloquant solutuon.

Solaris' /bin/awk is old and broken. Use either /bin/nawk or /usr/xpg4/bin/awk on Solaris.
On most/some of the other OSs, 'awk' is linked symbolcally to 'nawk'
Once the 'match' is found, we 'skip' (next) the number of lines (initialized at the finding of the match to 5).
When 'n!=0' (all to be skipped lines have been skipped), we print lines 'as is' - '1' is the equivalent of '{print $0}'.