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1. Programming
Hello !
I'm creating a CGI which allow to display graph from some data.
The datas looks like :
2020-01-13-00-00,384.00,350.00
2020-01-13-06-00,384.00,350.00
2020-01-13-12-00,384.00,350.00
2020-01-13-18-00,384.00,350.00
2020-01-14-00-00,384.00,350.00... (1 Reply)
Discussion started by: Tim2424
1 Replies
2. Shell Programming and Scripting
Hi,
I have been stuck in this requirement where my file contains the below format.
20150812170500846959990854-25383-8.0.0
"ABC Report" hp96880
"4952"
20150812170501846959990854-25383-8.0.0 End of run
20150812060132846959990854-20495-8.0.0
"XYZ Report" vg76452
"1006962188"... (6 Replies)
Discussion started by: Chinmaya Kabi
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3. Shell Programming and Scripting
Heyas
Trying to calculate the total size of a file by reading its bitrate.
Code snippet:
fs_expected() { #
# Returns the expected filesize in bytes
#
pr_str() {
ff=$(cat $TMP.info)
d="${ff#*bitrate: }"
echo "${d%%,*}" | $AWK '{print $1}' | head -n 1
}
t_BYTERATE=$((... (9 Replies)
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9 Replies
4. Shell Programming and Scripting
Hi guys,
could someone throw some light on the following behaviour of printf (I'll start with info about the system and the tool/shell/interpreter versions)?:
$ uname -a
Linux linux-86if.site 3.1.0-1.2-desktop #1 SMP PREEMPT Thu Nov 3 14:45:45 UTC 2011 (187dde0) x86_64 x86_64 x86_64... (9 Replies)
Discussion started by: elixir_sinari
9 Replies
5. Shell Programming and Scripting
Hello,
I need to format a number..like 12900 should be printed as 12,900
and 1209 as 1,209 and so on. (Just like we do in excel).
Can this be done in awk. any printf options we have?Please suggest me.
Thanks! (8 Replies)
Discussion started by: vijay_0209
8 Replies
6. Shell Programming and Scripting
Hi
I'm using awk to manipulate the data in the 6th field of the file xxx_yyy.hrv.
The sample data that is available in this field is given below
220731.7100000000000000
When i tried using this command
cat xxx_yyy.hrv | awk '{printf("%23.16f\n",$6*-1)}'
I get the output as... (4 Replies)
Discussion started by: angelarosh
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7. Shell Programming and Scripting
Hi All,
can some body help me to script the below logic. Basically am facing
problem with float calculation. Also i need this to be done inside a single awk.
I tried lot of tuning but still nothing is getting displayed, nor any errors
param=50
value=19.23
for(i=0;i<4;i++)
{... (2 Replies)
Discussion started by: jisha
2 Replies
8. Programming
Good morning,
I'm testing the use of ceilf:
/*Filename: str.c*/
#include <stdio.h>
#include <math.h>
int main (void)
{
float ceilf(float x);
int dev=3, result=0;
float tmp = 3.444f;
printf("Result: %f\n",ceilf(tmp));
return 0;
} (1 Reply)
Discussion started by: jonas.gabriel
1 Replies
9. Shell Programming and Scripting
Hi all,
I'm looking to modify a script to check disk space usage.
Here is the code at the moment:
#
# The control file, MONITOR_DISK_SPACE, must be in the format ... Drive:;threshold_percentage
# eg.
# C:;95
# D:;98
# E:;90
#
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10. UNIX for Dummies Questions & Answers
Hi,
I have a script which takes a value from a file and performs calculations on it. Trouble is that this value is a float not an integer and it errors at the decimal point!
eg. 94.62
I would like to be able to detect the length of the float (in this above case, 5 characters), and simply do a... (2 Replies)
Discussion started by: danhodges99
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bup-margin(1) General Commands Manual bup-margin(1)
NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS
--predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO
bup-midx(1), bup-save(1)
BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown- bup-margin(1)