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problem with awk command

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# 1  
Old 07-29-2010
problem with awk command
I have written some code in a KSH script to find the index of the character in a string like this

Code:
#!usr/bin/ksh

string="Hi How are you"
awk 'BEGIN {print index ($string, "are")}'

My expected output should be : 8
but it is giving the out put as : 0

I wanted to store that index value in a variable. Can anyone please help me in this

Also I am trying to get a substring of the above string by providing the start index and end index and store the substring in another variable. I am not getting any clue how to do that.

Guyz please help
# 2  
Old 07-29-2010
Hi.

In your code, string is a shell variable, not an awk one:

Code:
$ awk -v s="$string" 'BEGIN {print index (s, "are")}'
8

(usr nawk or /usr/xpg4/bin/awk on Solaris)
# 3  
Old 07-29-2010
Data
I am not getting the expected output Smilie

I wrote the code like this

Code:
#!/usr/bin/ksh
echo "-------START-----"
string="Hi How are you"
awk -v s="$string" 'BEGIN {print index (s, "are")}'
echo "-------END-------"

The output is:

Code:
-------START-----
awk: syntax error near line 1
awk: bailing out near line 1
-------END-------

# 4  
Old 07-29-2010
Hi.

As I said above:

Quote:
(usr nawk or /usr/xpg4/bin/awk on Solaris)
The old, cruddy awk on Solaris doesn't understand much, -v being one thing.
# 5  
Old 07-29-2010
I am not getting you. do you want me to try this way?

Code:
#!/usr/xpg4/bin/awk
echo "-------START-----"
string="Hi How are you"
awk -v s="$string" 'BEGIN {print index (s, "are")}'
echo "-------END-------"

# 6  
Old 07-29-2010
Hi.

No, I meant:

Code:
#!/usr/bin/ksh
echo "-------START-----"
string="Hi How are you"
nawk -v s="$string" 'BEGIN {print index (s, "are")}'
echo "-------END-------"

Or

Code:
#!/usr/bin/ksh
echo "-------START-----"
string="Hi How are you"
/usr/xpg4/bin/awk -v s="$string" 'BEGIN {print index (s, "are")}'
echo "-------END-------"

# 7  
Old 07-29-2010
Code:
string="Hi How are you"
expr index "$string" "are"
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