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Shell Programming and Scripting

Input and value problem

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# 1  
Old 07-22-2010
Input and value problem
Hi, I need to convert given cents to dollars so I have a script with this this:

Code:
A=$(echo "$1*0.01" | bc)
echo $A

B=$(echo "$2*0.01" | bc)
echo $B

C=$(echo "$3*0.01" | bc)
echo $C

D=$(echo "$4*0.01" | bc)
echo $D

E=$(echo "$5*0.01" | bc)
echo $E

F=$(echo "$6*0.01" | bc)
echo $F

G=$(echo "$7*0.01" | bc)
echo $G

H=$(echo "$8*0.01" | bc)
echo $H

I=$(echo "$9*0.01" | bc)
echo $I

J=$(echo "$10*0.01" | bc)
echo $J

K=$(echo "$11*0.01" | bc)
echo $K

L=$(echo "$12*0.01" | bc)
echo $L

When I run that I get:

Code:
[root@Blah Script]# ./test 1234 1234 1234 1234 1234 1234 1234 1234 1234 1234 1234 1234
12.34
12.34
12.34
12.34
12.34
12.34
12.34
12.34
12.34
123.40
123.41
123.42

Notice that it works just fine except for the las three ($10, $11, $12).
Any ideas on how to make it work?

Thanks!
# 2  
Old 07-22-2010

Positional parameters greater than 9 must be enclosed in braces:
Code:
printf "%s\n" "${10}" "${11}" "${12}"

Otherwise, $10 is interpreted as ${1}0
# 3  
Old 07-22-2010
Quote:
Originally Posted by cfajohnson

Positional parameters greater than 9 must be enclosed in braces:
Code:
printf "%s\n" "${10}" "${11}" "${12}"

Otherwise, $10 is interpreted as ${1}0
Thank you!
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