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what does the below mentioned command do?

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# 1  
Old 07-19-2010
what does the below mentioned command do?
Hi,
Can someone please help as to what does the below mentioned command do?

Code:
root=$(echo $0|sed 's#extras/package/win32/configure-msys.sh##')./

here,when I simply echo $0 i get
Code:
 ..\..\..\..\..\..\msys\1.0\home\admin\vlc\extras\package\win32\configure-msys.sh

Last edited by Scott; 07-19-2010 at 07:31 AM.. Reason: Code tags
# 2  
Old 07-19-2010
Hi.

Whatever it's supposed to do, it doesn't work. The slashes are the wrong ones!

If they were the right ones, the output would be:
Code:
$ cat Test1
# imagine X is $0!
X=" ..\..\..\..\..\..\msys\1.0\home\admin\vlc\extras\package\win32\configure-msys.sh"

root=$(echo $X|sed 's#extras/package/win32/configure-msys.sh##')./
echo What it is doing: $root

X=$(echo $X | tr '\' '/')
root=$(echo $X|sed 's#extras/package/win32/configure-msys.sh##')./
echo What I guess it should be doing: $root

$ ./Test1
What it is doing: ..\..\..\..\..\..\msys\1.0\home\admin\vlc\extras\package\win32\configure-msys.sh./
What I guess it should be doing: ../../../../../../msys/1.0/home/admin/vlc/./

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