Shell Programming and Scripting

Is "filename" in your current directory? If not, you may not want to split the unqualified filename out. grep doesn't mind a fully qualified file name.

Try removing these lines:

Code:

        @a=split "/",$output;
        $output=$a[4];

Everything else looks perfect.

Hi,

If I understand you right....You wanted me to give the full path to the file rather than just the file name. But no luck.

Any other ideas or things that might cause this.

I am new to perl and I need to complete this by Tuesday.

Thanks
nurani

chomp($output);

Since $output was the last field in the record you split, the newline is probably still attached as part of the filename (yes, a newline can be part of a filename.) The actual file name you're interested does not contain the newline. "filename\n" is quite a bit different than "filename". This is 97% guaranteed to work.

Hi,

I have tried everything that has been suggested, but to no avail. Let me explain exactly what I am doing. (Or what I want the script to do)

1) I run my script in machine A
2) I need to grep the log files for "Number of orders processed". But these log files are sitting in machine B.

So, I am using the remsh command in a foreach loop to scan all the machines.

Once I find the log file, I am doing the Grep. My Grep is given below

Code:

grep "Number of jobs processed:" $output | sort -u | awk '{print $5}'`;

Any other suggestions that you can think of. I need to have this resolved by Tomorrow (Wednesday). Any help is very much appreciated.

Thanks
nurani