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problem with path extract from file

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# 1  
Old 06-28-2010
problem with path extract from file
hello,

i have a configuration file app.conf under /tmp, containing values like :
param1=/data/something
param2=/data/somethingelse

i have a bash script that has to list the files under the path that corresponds to param2 :

#!/bin/bash
dir=$(cat tmp/app.conf | grep param2 | sed "s/param2//")
echo "path needed"
echo $dir
Until here, everything is fine, i get /data/somethingelse shown on the console.


ls $dir -> gives me this error :
: No such file or directory

Could anyone help me with this one ?

Thanks a lot,
Chaa
# 2  
Old 06-28-2010
Try
Code:
ls "$dir"

# 3  
Old 06-28-2010
the "sed" pattern should be:

Code:
sed "s/param2=//"

hence, the second line should look like:

Code:
dir=$(cat tmp/app.conf | grep param2 | sed "s/param2=//")

otherwise the dir variable has the "=" at the beginning.
Last edited by Franklin52; 06-28-2010 at 05:39 PM.. Reason: Please use code tags
# 4  
Old 06-28-2010
thank you both for your answers
actually
this is what i wrote in the bash :
Code:
dir=$(cat tmp/app.conf | grep param2 | sed "s/param2=//")

and
Code:
ls "$dir"

isn't working either...
Last edited by Franklin52; 06-28-2010 at 05:40 PM.. Reason: Please use code tags
# 5  
Old 06-28-2010
Maybe there just isn't such directory on your system Smilie Try using "ls" on command line with that directory:
Code:
ls /data/somethingelse

# 6  
Old 06-28-2010
Quote:
Originally Posted by chaa
thank you both for your answers
actually
this is what i wrote in the bash : dir=$(cat tmp/app.conf | grep param2 | sed "s/param2=//")

and
ls "$dir"
isn't working either...
can you post the output of ls command?
# 7  
Old 06-28-2010
What isn't working? What is the content of $dir ? Any messages?

I think you need to supply an absolute path ( /tmp/ instead of tmp/ )
Also, the selecting statement can be further optimized:
Code:
dir=$(sed -n "s/param2=//p" /tmp/app.conf)

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