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Full Discussion: problem with path extract from file
Top Forums Shell Programming and Scripting problem with path extract from file Post 302433121 by rugdog on Monday 28th of June 2010 03:20:58 PM
Old 06-28-2010
the "sed" pattern should be:

Code:
sed "s/param2=//"

hence, the second line should look like:

Code:
dir=$(cat tmp/app.conf | grep param2 | sed "s/param2=//")

otherwise the dir variable has the "=" at the beginning.
Last edited by Franklin52; 06-28-2010 at 05:39 PM.. Reason: Please use code tags
 

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LEARN ABOUT MINIX

zgrep

ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep  options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

                                                                                                                                          ZGREP(1)
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