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handling multiple files using awk command and wants to get separate out file for each


 
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# 1  
MySQL handling multiple files using awk command and wants to get separate out file for each

hai all
I am new to the world of shell scripting

I wanted to extract two columns from multiple files say around 25 files
and i wanted to get the separate outfile for each input file

tired using the following command to extract two columns from 25 files

Code:
awk '/ATOM/ {print $4,$6}' *.A.pdb >all.txt


files names are like 1_A.pdb, 2_A.pdb, ... 25_A.pdb

but the problem is, its giving everything in a single file i dont want to get it like that
is there any other way to get separate files for each input file



please help me in this regard

thanks lot for ur time
Hema


Moderator's Comments:
Mod Comment Added code tags.

Last edited by radoulov; 05-13-2010 at 06:13 AM..
# 2  
put it in a for loop
Code:
for F in *.A.pdb
do
    awk '/ATOM/ {print $4,$6}' $F  >${F%.A.pdb}.txt
done

${F%.A.pdb} is to remove .a.pdb at end of filename
# 3  
MySQL

thank a lot
its working fine

Hema

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