Shell Programming and Scripting

Even though the idea "might" not be great I still wrote this piece of code to get practice.. Which means that it is the CODE that matters here.

Anyways;

The intension is to create a program(or do we call it script?) that searches recursively through a folder to find a file - stored in a folder - and then allocate an environment variable for this specific location which is given the name of the folder itself.

Errrh

In other words, the folder /home/myusername/bash/myscript/ would get an environment variable called 'myscript' with the value '/home/myusername/bash/myscript/' ...if it has a file whose name is stored in $CREATE_VAR_OK

Here's the code that doesn't work though:

Code:

## Currently in the folder that is going to searched...
## lets pray that there are no files with spaces! :cool:
for filecheck in $(ls -A) 
  do
    case $filecheck in
      $CREATE_VAR_OK) eval ${PWD##*/}=$PWD ; echo set ${PWD##*/} for $PWD ; eval export ${PWD##*/};;
    esac
  done

($CREATE_VAR_OK is ".CREATE_LINK" which is a file put in all the folders I want to create a variable for)

If I add "env" in the case check (; env; ) it displays the variable located in the environment. However if I run env AFTER the script has been run it seems to be gone...

I might also add that the piece of code listed is in a FUNCTION. I chose not to put the entire piece of code out there now since I have some lazy coding that I'd like to hide unless I have to show

...The echo statement does also give out the correct name of the folder.

Hope this makes some sense..!

(extra question: is there anyways of avoiding to use ls here to view hidden files?)

Sorry to say that I have absolutely no idea what you're talking about

Is there any possibility that you can rephrase your question in such a way that it's comprehensible?

ok, rephrasal xD

Given the following piece of code put in a shell function..

Code:

for filecheck in $(ls -A) 
do
  case $filecheck in
    $CREATE_VAR_OK) eval ${PWD##*/}=$PWD ; echo set ${PWD##*/} for $PWD ; eval export ${PWD##*/};;
  esac
done

...Is there anyone who knows why my variable given the name ${PWD##*/} won't be extracted to the environment as long as the shell runs, but only during the runtime of the script?

.. (A)

From the man page of bash:

Code:

...
The supplied names are marked for automatic export to the environment of subsequently executed commands.
...

If I understood you right you expected to have that variable available in the environment/shell where you started the script from. This not the case since this shell is not a child of that script.

aaahaaaaa

well that makes sense

So that means I have to go the way of the fork() in C (or something like it) right? No need to put the code out here though really for my sake.

Thank you for clearing it up ..!