Validate time pattern using regular expression


 
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# 1  
Old 04-21-2010
Validate time pattern using regular expression

Hi,
I am new to scripting.
please help me in validating the user entered time Pattern
Here is the program

Code:
#!/bin/bash
validateTimeFormat()
{
checkTime=$1
timePattern="[0-2][0-9]:[0-5][0-9]:[0-5][0-9]"
if [[ $checkDate =~ $timePattern ]]
then
echo "Valid time pattern"
return 1
else
echo "InValid time pattern"
return -1
fi
}
echo "Please enter the end time [hh:mm:ss]"
read END_TIME
echo "Time entered is $END_TIME"
validateTimeFormat $END_TIME
if [ $? -ne "1" ];
then
echo "Time format entered is wrong"
exit 0
fi


Last edited by pludi; 04-21-2010 at 09:39 AM.. Reason: code tags, please...
# 2  
Old 04-21-2010
Quote:
Originally Posted by vvenu88
Hi,
I am new to scripting.
please help me in validating the user entered time Pattern
Here is the program
...
So what's your question ?
How do we help you in validating the user entered time Pattern ?

tyler_durden
# 3  
Old 04-21-2010
if have GNU date you can validate using it
Code:
validateTimeFormat()
{
  if date -d "$1" >/dev/null # you can enventually remove redirection...
  then
    echo "Valid time pattern"
    return 0
  else
    echo "InValid time pattern"
    return 1
  fi
}

if you don't need to echo anything but just check, it would be
Code:
date -d "$1" >/dev/null
# which returns 0 (true if OK)

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