Shell Programming and Scripting

also you might be interesting in this simple solution

Code:

ls -ltr | awk '{if ($5!=0) print $0}'

if 5th column is not 0 then print whole line.

Hi.

With an awk filter:

Code:

ls -ltr | awk '$5 != 0'

which uses an arithmetic comparison.

The awk processor implicitly reads lines and breaks them apart into fields that are numbered $1, $2, etc. One can then check the content of these fields in a number of ways, one being arithmetically.

So the above code means print each line where field 5 is not zero. Many awk scripts are complex, but many are simple, and often are easily constructed when dealing with operations that are naturally numeric. Regular expressions may still be used, but that's a different story.

There are controls that can change the settings for what characters separate the fields, etc., but the defaults are usually acceptable for many cases.

For the data posted, this produced:

Code:

-rw-r--r-- 1 userID MyGroup 50 Mar 2 10:27 c.txt
-rw-r--r-- 1 userID MyGroup 200 Mar 2 11:24 e.txt
-rw-r--r-- 1 userID MyGroup 100 Mar 4 03:14 g.txt

Best wishes ... cheers, drl

(The columns in the above output do not line up because the data was not originally posted within CODE tags.)

It is the same solution as mine but written in shorter form (not very explaining for awk begginer)

It could be also written like this:

Code:

ls -ltr | awk \$5

With zsh:

Code:

ls -ltr  *(^L0)

Code:

find . -size +0 -exec ls -lctr {} \;

And if the order is irrelevant:

Code:

find . -size 0 -ls