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Choose a single word from a wordlist by matching the letters it contains?

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# 29  
Old 03-15-2010
radoulov is the below will include all the char ranges I just take the complement of NULL \0 char and it worked like a charm...test it man.do you like it?

Code:
perl -lne 'BEGIN{$l=join "", sort split //,shift ; $l =~ tr/\0//cs }
$w=join "",sort split // ;$w =~ tr/\0//cs; print if $w eq $l ;' 'nniomscta' wordlist

SmilieSmilieSmilieSmilieSmilieSmilieSmilie
# 30  
Old 03-15-2010
Quote:
Originally Posted by ahmad.diab
radoulov is the below will include all the char ranges I just take the complement of NULL \0 char and it worked like a charm...test it man.do you like it?[...]
I was referring to:

Code:
tr/A-Za-z0-9//cs

in your previous post.

Yep, it's rather good using the NULL character (assuming, of course, the NULL characters is not present and it shouldn't be, assuming the input file is a text file Smilie).
# 31  
Old 03-15-2010
Thanks for feedback.
SmilieSmilieSmilieSmilieSmilie
# 32  
Old 03-15-2010
You're welcome!
# 33  
Old 03-15-2010
perl may be the better solution, below case is to find the word that are only composed of 'a','b','c' and each of them appear once.

Code:
while(<DATA>){
	my @tmp = split;
	foreach(@tmp){
		if(/^(?=[bc]*a)(?=[ac]*b)(?=[ab]*c)[abc]*$/){
			if(length($_)==3){
				print $_,"\n";
			}
		}
	}
}
__DATA__
begin
ab abc
abccc
abcd
a
bac
ccc
abb
abc abc
end
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