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FS Growth Graph

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# 1  
Old 03-10-2010
FS Growth Graph
It's been a while since i've been here.. and hopefully you can help me.
I have created a script to get the filesystem utilization. Now i want to create a growth graph, which would show how much kb we increase per day.

Here's the data
Code:
03-02-2010 00:00:00: /dev/md/dsk/d30      46473377 7355320 38653324    16%    /
03-03-2010 00:00:00: /dev/md/dsk/d30      46473377 7357826 38650818    16%    /
03-04-2010 00:00:00: /dev/md/dsk/d30      46473377 7357834 38650810    16%    /
03-05-2010 00:00:00: /dev/md/dsk/d30      46473377 7380646 38627998    17%    /
03-06-2010 00:00:00: /dev/md/dsk/d30      46473377 7881059 38127585    18%    /
03-07-2010 00:00:00: /dev/md/dsk/d30      46473377 7882001 38126643    18%    /
03-08-2010 00:00:00: /dev/md/dsk/d30      46473377 7365537 38643107    17%    /
03-09-2010 00:00:00: /dev/md/dsk/d30      46473377 7373164 38635480    17%    /
03-10-2010 00:00:00: /dev/md/dsk/d30      46473377 7373172 38635472    17%    /

I want to get the used space from the previous day to current day?
I need it to be added at the last column.

Code:
#!/bin/sh

util=`df -k / | grep '/dev/md/dsk/d30'`
echo "`date +\"%m-%d-%Y %H:%M:%S\"`: $util" >> file.out
exit 0

# 2  
Old 03-10-2010
Try this one:

Code:
util=`df -k / | sed -n '3,3p' | awk '{print $1}'`
echo "`date +\"%m-%d-%Y %H:%M:%S\"`: $util" >> file.out

# 3  
Old 03-10-2010
First you can update the file file.out with:
Code:
awk 'NR==1{last=$5;print;next}{print $0, $5-last; last=$5}
' file.out > tempfile

mv tempfile file.out

Then you can use this script to add the increment per day:
Code:
#!/bin/sh

util=`df -k / | grep '/dev/md/dsk/d30'`
prev=`tail -1 file.out|awk '{print $5}'`
last=`echo "$util"|awk '{print $5}'`
grow=$(( $last - $prev ))
echo "`date +\"%m-%d-%Y %H:%M:%S\"`: $util $grow" >> file.out
exit 0

Regards
# 4  
Old 03-10-2010
Code:
awk 'NR==1{last=$6;print}NR>1{if ($6 < last){print $0,last -$6} else print $0,-($6-last);last=$6}' file

# 5  
Old 03-11-2010
thanks all.. this should work for the requirements. Smilie
# 6  
Old 03-11-2010
Shorter code
Code:
 awk 'NR==1{last=$6;$(NF+1)=0}NR>1{$(NF+1)=last-$6;last=$6}1' file.out

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