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Added new line before a specific pattern problem asking

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# 8  
Old 03-08-2010
Hi patrick87,
What is your requirement whether that pattern will in the third column or anywhere in the line.
devtakh's solution seems to correct,but its not exactly correct,because he is matching the pattern in line.He has not match the pattern with the third column.
His solution will work for the following input also.

Code:
Sample1 pattern 842 3150
Sample1 range 842 3150
Sample1 pattern 842 1127
Sample1 option 842 1127
Sample1 length 1483 1603
Sample1 pattern 1483 1603
Sample1 length 1698 1747
Sample1 option 1698 1747
Sample1 length 1868 1935
Sample1 pattern 1868 1935
Sample1 length 2164 2262

Here the pattern is in the second column.
# 9  
Old 03-08-2010
Awk solution...

Code:
awk '$3=="pattern"{print "\n"$0;next}1' infile

# 10  
Old 03-08-2010
Try:

Code:
awk '/pattern/&&NR>1 { print RS; }NR' file

# 11  
Old 03-08-2010
If specific to a column, ignoring extra line if matches in the first line itself.

Code:
sed  '2,$s/\([^ ]*\)\( .*\)\( pattern\)\(.*\)/\n\1\2\3\4/' file


cheers,
Devaraj Takhellambam
# 12  
Old 03-08-2010
Try this script,

Code:
#!/bin/sh
while read line
do
        val=` echo $line | cut -d " " -f 3 `
        if [[ $val == "pattern" ]]
        then
                echo -e "\n$line"
        else
                echo $line
        fi
done < inputfile

# 13  
Old 03-08-2010
Hi malcomex999,
Your awk solution worked perfectly to my case too Smilie
Thanks a lot.
# 14  
Old 03-08-2010
Quote:
Originally Posted by dennis.jacob
Try:

Code:
awk '/pattern/&&NR>1 { print RS; }NR' file

If you are looking for appatern in third col, try:

Code:
awk '$3 ~ /pattern/&&NR>1 { print RS"\b" ;} NR ' file
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