awk $NF question


 
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# 1  
Old 02-09-2010
awk $NF question

Hi there I have a script which uses awks "{print $NF} function to print the last field in a space delimited line

it turns out that the output i am awking against has changed and now i need to get the 3rd column in from the right (the one highlighted in red below). Is there an easy way to do this by using $NF and counting backwards, or am i going to have to do a field count from the left ?



Code:
Product Name          : INTEL(R) XEON(R) CPU           E5540  @ 2.53GHZ

any help would be great
# 2  
Old 02-09-2010
Hi

Code:
print $(NF-2)

# 3  
Old 02-09-2010
thanks Scott, I seem to be having a few issues with that ... let me paste my code

My original command to retrieve the last field was

Code:
 # ipmitool fru | nawk '!NF{f=0};/(p0.fru|MB\/P0 \()/{f=1} ; /Product Name/&&f{print $NF}'

Ive tried a few variations of adding the -2 to the final print command with no success, for example


Code:
 # ipmitool fru | nawk '!NF{f=0};/(p0.fru|MB\/P0 \()/{f=1} ; /Product Name/&&f{print NF-2}'
7


Could you let me know how this would work because obviously NF-2 will will just give me 7 (i.e the correct field number)
# 4  
Old 02-09-2010
How about if you try this...

Code:
ipmitool fru | nawk '!(NF-2){f=0};/(p0.fru|MB\/P0 \()/{f=1} ; /Product Name/&&f{print $(NF-2)}'

# 5  
Old 02-09-2010
its ok i got it (misread the folowing as something else - DOH)

$(NF-2)
# 6  
Old 02-09-2010
Quote:
Originally Posted by rethink
its ok i got it

$(NF-2)
Smilie
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