sed print all lines after pattern match


 
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# 1  
Old 12-30-2009
sed print all lines after pattern match

HiCan someone show me how to print all lines from a file after a line matching a pattern using sed?Thanks
# 2  
Old 12-30-2009
try
Code:
sed '1,/regex/d'

will not include the first pattern line.

example:
Code:
$ cat data
123
ABC
DEF
GHI
$ sed '1,/A/d' data
DEF
GHI

# 3  
Old 12-30-2009
Thanks. Doesn't quite work perhaps because I am trying to pipe the lines through sed rather than read a file. What I am trying to do is lose the message of the day on stdout when running a command though ssh by preceding the command with an echo of a string "PARSE_FROM_HERE". The intention is to lose all of the MOTD stuff and just pick up the ls output. I have trouble posting code from here so I hope this is not too garbled, if so I will post it tonight: -
Code:
ssh [IP ADDRESS] "echo PARSE_FROM_HERE;ls -lrt" | sed '1,/PARSE_FROM_HERE/d'

# 4  
Old 12-30-2009
Quote:
Originally Posted by steadyonabix
The intention is to lose all of the MOTD stuff and just pick up the ls output.
What about:
Code:
ssh [IP ADDRESS] "ls -lrt"

# 5  
Old 12-30-2009
Try:
Code:
sed '0,/PARSE_FROM_HERE/d'

# 6  
Old 12-30-2009
Quote:
Originally Posted by Scrutinizer
Try:
Code:
sed '0,/PARSE_FROM_HERE/d'

Smilie, that's right! I take a mistake.
# 7  
Old 12-30-2009
Code:
ssh [IP ADDRESS] "echo PARSE_FROM_HERE;ls -lrt " |sed '0,/PARSE_FROM_HERE/d'

This gives me the MOTD, the PARSE_FROM_HERE line and the ls output. If I substitute a 1 for the 0 I get the MOTD and nothing from the PARSE_FROM_HERE line. Which seems to be the opposite of what is expected from redraiment's results above.
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