Sponsored Content
Top Forums Shell Programming and Scripting sed print all lines after pattern match Post 302383557 by steadyonabix on Wednesday 30th of December 2009 07:05:31 AM
Old 12-30-2009
Thanks. Doesn't quite work perhaps because I am trying to pipe the lines through sed rather than read a file. What I am trying to do is lose the message of the day on stdout when running a command though ssh by preceding the command with an echo of a string "PARSE_FROM_HERE". The intention is to lose all of the MOTD stuff and just pick up the ls output. I have trouble posting code from here so I hope this is not too garbled, if so I will post it tonight: -
Code:
ssh [IP ADDRESS] "echo PARSE_FROM_HERE;ls -lrt" | sed '1,/PARSE_FROM_HERE/d'

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Sed to delete exactly match pattern and print them in other file

Hi there, I need help about using sed. Iam using sed to delete and print lines that match the port number as listed in sedfile. I am using -d and -p command for delete match port and print them respectively. However, the output is not synchonize where the total deleted lines is not similar with... (3 Replies)
Discussion started by: new_buddy
3 Replies

2. Shell Programming and Scripting

Perl script to match a pattern and print lines

Hi I have a file (say 'file1')and I want to search for a first occurence of pattern (say 'ERROR') and print ten lines in the file below pattern. I have to code it in PERL and I am using Solaris 5.9. I appreciate any help with code Thanks Ammu (6 Replies)
Discussion started by: ammu
6 Replies

3. Shell Programming and Scripting

print chunk of lines only if there is a pattern match in between them

Hi All, Please find the sample file below: NAME ID NUMBER -------------------------------------------------------------------------------------------------- --------- abcdefgheija;lksdf ... (13 Replies)
Discussion started by: niel.verty
13 Replies

4. Shell Programming and Scripting

print lines with exact pattern match

I have in a file domain.com. 1909 IN A 1.22.33.44 domain.com. 1909 IN A 22.33.44.55 ns1.domain.com. 1699 IN A 33.44.55.66 ns2.domain.com. 1806 IN A 77.77.66.66 I need to "grep" or "awk" out the lines starting with domain.com. as follows. domain.com. 1909 IN A 1.22.33.44 domain.com.... (3 Replies)
Discussion started by: anilcliff
3 Replies

5. Shell Programming and Scripting

Print lines before and after pattern match

I am using Solaris, I want to print 3 lines before pattern match pattern 5 lines after pattern match Pattern is abcd to be searched in a.txt. Looking for the solution in sed/awk/perl. Thanks .. Input File a.txt: ================= 1 2 3 abcd 4 5 6 7 8 (7 Replies)
Discussion started by: manuswami
7 Replies

6. Shell Programming and Scripting

Need one liner to search pattern and print everything expect 6 lines from where pattern match made

i need to search for a pattern from a big file and print everything expect the next 6 lines from where the pattern match was made. (8 Replies)
Discussion started by: chidori
8 Replies

7. Shell Programming and Scripting

Print lines that do not match the pattern

I need to print the lines that do not match a pattern. I tried using grep -v and sed -n '/pattern/!p', but both of them are not working as I am passing the pattern as variable and it can be null some times. Example ........ abcd...... .........abcd...... .........abcd......... (4 Replies)
Discussion started by: sunny1234
4 Replies

8. Shell Programming and Scripting

awk print pattern match line and following lines

Data: Pattern Data Data Data Data Data Data Data Data Data ... With awk, how do I print the pattern matching line, then the subsequent lines following the pattern matching line. Varying number of lines following the pattern matching line. (9 Replies)
Discussion started by: dmesserly
9 Replies

9. Shell Programming and Scripting

Match Pattern and print pattern and multiple lines into one line

Hello Experts , require help . See below output: File inputs ------------------------------------------ Server Host = mike id rl images allocated last updated density vimages expiration last read <------- STATUS ------->... (4 Replies)
Discussion started by: tigerhills
4 Replies

10. Shell Programming and Scripting

sed -- Find pattern -- print remainder -- plus lines up to pattern -- Minus pattern

The intended result should be : PDF converters 'empty line' gpdftext and pdftotext?xml version="1.0"?> xml:space="preserve"><note-content version="0.1" xmlns:/tomboy/link" xmlns:size="http://beatniksoftware.com/tomboy/size">PDF converters gpdftext and pdftotext</note-content>... (9 Replies)
Discussion started by: Klasform
9 Replies
SSH-LDAP-HELPER(8)					    BSD System Manager's Manual 					SSH-LDAP-HELPER(8)

NAME
ssh-ldap-helper -- sshd helper program for ldap support SYNOPSIS
ssh-ldap-helper [-devw] [-f file] [-s user] DESCRIPTION
ssh-ldap-helper is used by sshd(1) to access keys provided by an LDAP. ssh-ldap-helper is disabled by default and can only be enabled in the sshd configuration file /etc/ssh/sshd_config by setting AuthorizedKeysCommand to ``/usr/libexec/openssh/ssh-ldap-wrapper''. ssh-ldap-helper is not intended to be invoked by the user, but from sshd(8) via ssh-ldap-wrapper. The options are as follows: -d Set the debug mode; ssh-ldap-helper prints all logs to stderr instead of syslog. -e Implies -w; ssh-ldap-helper halts if it encounters an unknown item in the ldap.conf file. -f ssh-ldap-helper uses this file as the ldap configuration file instead of /etc/ssh/ldap.conf (default). -s ssh-ldap-helper prints out the user's keys to stdout and exits. -v Implies -d; increases verbosity. -w ssh-ldap-helper writes warnings about unknown items in the ldap.conf configuration file. SEE ALSO
sshd(8), sshd_config(5), ssh-ldap.conf(5), HISTORY
ssh-ldap-helper first appeared in OpenSSH 5.5 + PKA-LDAP . AUTHORS
Jan F. Chadima <jchadima@redhat.com> BSD
April 29, 2010 BSD
All times are GMT -4. The time now is 10:09 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy