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regular expression in ksh

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# 1  
Old 11-30-2009
Question regular expression in ksh
I am trying to test to see if the hostname of the computer I'm on starts with ne1dxdb - it can contain any characters after that. I have the following code, but it's not working - it's not falling into the if statement. Any ideas?

boxname="unknown"

function get_hosttype {
HOSTNAME=`hostname`

if [ ${HOSTNAME} = ne1dxdb* ]
then
export boxname="test"
fi
if [ ${HOSTNAME} = ne1pxdb* ]
then
export boxname="prod"
fi
}
# 2  
Old 11-30-2009
You have to use [[ ... ]] instead of [ ... ] to use pattern matching in ksh.
# 3  
Old 11-30-2009
What you are looking is not full regular expression but simple file expansion like pattern matching.
Instead of using multiple if/then statements, the shell case/esac syntax seems the simpler solution to achieve what you want:
Code:
function get_hosttype
{
  export boxname=unknown
  case $(hostname) in
  (ne1dxdb*) boxname=test;;
  (ne1pxdb*) boxname=prod;;
  esac
}

Scrutinizer suggestion will work too.
Last edited by jlliagre; 11-30-2009 at 10:11 PM.. Reason: Add some explanations
# 4  
Old 11-30-2009
from man ksh :
Quote:
string =∼ ere
True if string matches the pattern ∼(E)ere where ere is an extended regular expression.
to be used with double square brackets
# 5  
Old 11-30-2009
regular expression in ksh
it is the problem with quotes, i think juct change like below and try...

function get_hosttype {
HOSTNAME=`hostname`

if [ "${HOSTNAME}" = "ne1dxdb*" ]
then
export boxname="test"
fi
if [ "${HOSTNAME}" = "ne1pxdb*" ]
then
export boxname="prod"
fi
}
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